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3 years ago

Help I have a photo of the problem

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

4 0

Answer:

Step-by-step explanation:

The mistake was: he is suppose to substract 1/2x from both side not add 1/2x

3/4x + 5 = 1/2(x - 8)

3/4x + 5 = 1/2x - 4

Substracting 1/2x from both side

3/4x - 1/2x + 5 = 1/2x - 1/2x - 4

3/4x - 1/2x + 5 = -4

3/4x - 1/2x = -4 - 5

3/4x - 1/2x = -9

Multiple each term by 4

3x - 2x = 4(-9)

x = -36

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Step-by-step explanation:

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3 years ago

I’m stuck can some one help me

abruzzese [7]

Answer:

3) Midpoint is (-4,0.5)

Option A is correct.

4) Midpoint is (2.5,0)

Option B is correct.

5) The factors are (x+4)(x-7)

Option C is correct.

6) The factors are (x+4)(x+2)

Option A is correct.

Step-by-step explanation:

Question 3

Find midpoint of the following:

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The formula used to find midpoint is: $Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$

We have $x_1=2, y_1=-7, x_2=-10,y_2=8$

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$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2-10}{2},\frac{-7+8}{2} )\\Midpoint=(\frac{-8}{2},\frac{1}{2} )\\Midpoint=(-4,0.5 )$

So, Midpoint is (-4,0.5)

Option A is correct.

Question 4

Find midpoint of the following:

(2,-10), (3,10)

The formula used to find midpoint is: $Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$

We have $x_1=2, y_1=-10, x_2=3,y_2=10$

Putting values and finding midpoint

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2+3}{2},\frac{-10+10}{2} )\\Midpoint=(\frac{5}{2},\frac{0}{2} )\\Midpoint=(2.5,0 )$

So, Midpoint is (2.5,0)

Option B is correct.

Question 5

Factor each completely

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We will break the middle term and find factors

$x^2-3x-28\\=x^2-7x+4x-28\\Taking\:common\\=x(x-7)+4(x-7)\\=(x+4)(x-7)$

So, the factors are (x+4)(x-7)

Option C is correct.

Question 6

Factor each completely

$x^2+6x+8$

We will break the middle term and find factors

$x^2+6x+8\\=x^2+4x+2x+8\\=x(x+4)+2(x+4)\\=(x+4)(x+2)$

So, the factors are (x+4)(x+2)

Option A is correct.

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3 years ago

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3 years ago

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6 0

3 years ago

An average computer mouse inspector can inspect 50 mice per hour. The 48 computer mice inspectors at a particular factory can on

Ronch [10]

Answer: C. Yes, because -2.77 falls in the critical region .

Step-by-step explanation:

Let $\mu$ be the population mean .

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Since the alternative hypothesis is left-tailed and population standard deviation is not given , so we need to perform a left-tailed t-test.

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Also, it is given that ,

n= 48

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s= 10

$t=\dfrac{46-50}{\dfrac{10}{\sqrt{48}}}=\dfrac{-4}{\dfrac{10}{6.93}}\\\\=\dfrac{-4}{1.443}\approx-2.77$

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Since, the absolute t-value (|-2.77|=2.77) is greater than the critical value.

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Hence, the correct answer is C. Yes, because -2.77 falls in the critical region

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4 years ago