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seropon [69]
3 years ago
11

Can someone help me with this?

Mathematics
1 answer:
Nesterboy [21]3 years ago
4 0

Answer:

36000pi

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

We know the surface area

SA = 4 pi r^2

3600 pi = 4 pi r^2

Divide each side by 4pi

3600 pi / 4pi= 4 pi r^2/4pi

900= r^2

Take the square root of each side

30 = r

Now substitute into the equation for volume

V = 4/3 pi r^3

   = 4/3(pi) (30)^3

    =36000pi

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Find the area of the trapezoid below to the nearest tenth.
kondor19780726 [428]

Answer:

Area of trapezoid = 67.6 square units

Step-by-step explanation:

Area of a trapezoid is given by the expression,

Area of the trapezoid = \frac{1}{2}(b_1+b_2)h

Here, b_1 and b_2 are the parallel sides of the given trapezoid.

And 'h' = Height between the parallel sides

From the given triangle ABE,

m(∠ABE) = m(∠ABC) - m(∠EBC)

m(∠ABE) = 120° - 90°

               = 30°

By applying cosine rule in the given triangle,

cos(30°) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

\frac{\sqrt{3} }{2}=\frac{BE}{AB}

\frac{\sqrt{3} }{2}=\frac{BE}{6}

BE = 3\sqrt{3} units

By applying sine rule in ΔABE,

sin(30°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

\frac{1}{2}=\frac{AE}{AB}

\frac{1}{2}=\frac{AE}{6}

AE = 3 units

Length of b_1=BC=10

Length of b_2=AD=(AE+EF+FD) [AE = FD, since given trapezoid ABCD is an isosceles trapezoid]

                b_2=3+10+3

                b_2=16

Height between the parallel sides h=3\sqrt{3}

Area of the trapezoid = \frac{1}{2}(BC+AD)BE

                                    = \frac{1}{2}(10+16)(3\sqrt{3})

                                    = 39\sqrt{3}

                                    = 67.6 square units

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3 years ago
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