This for loop will output:
0
2
4
The range(3) is all the integers between 0 inclusive and 3 exclusive. 0, 1, 2.
Every iterations through the for loop, we multiply the value of each number by 2 and print it to the console.
0 * 2 = 0
1 * 2 = 2
2 * 2 = 4
I hope this helps.
Answer:
Interrupt (INT) helps operating system to stop work on one process and start work on other process using interrupt signals.
Explanation:
Purpose of interrupts:
• Interrupts are useful when an I/O device needs to be serviced only occasionally at low data transfer rate.
• For example, when a peripheral requires the attention of the processor to perform an I/ O operation.
A trap:
• also known as an exception or a fault, is typically a type of synchronous interrupt caused by an exceptional condition
• is a software-generated interrupt.
• For example it's caused by division by zero or invalid memory access.
Can traps be generated intentionally by a user program? Yes.
If so, for what purpose?
• the usual way to invoke a kernel routine (a system call) because those run with a higher priority than user code.
• Handling is synchronous, so the user code is suspended and continues afterwards.
• In a sense they are active - most of the time, the code expects the trap.
Answer:
The program in Python is as follows:
num1 = int(input())
num2 = int(input())
if num1 >=0 and num2 >= 0:
print(num1+num2)
elif num1 <0 and num2 < 0:
print(num1*num2)
else:
if num1>=0:
print(num1**2)
else:
print(num2**2)
Explanation:
This gets input for both numbers
num1 = int(input())
num2 = int(input())
If both are positive, the sum is calculated and printed
<em>if num1 >=0 and num2 >= 0:</em>
<em> print(num1+num2)</em>
If both are negative, the products is calculated and printed
<em>elif num1 <0 and num2 < 0:</em>
<em> print(num1*num2)</em>
If only one of them is positive
else:
Calculate and print the square of num1 if positive
<em> if num1>=0:</em>
<em> print(num1**2)</em>
Calculate and print the square of num2 if positive
<em> else:</em>
<em> print(num2**2)</em>
