2) Intercepts are formed when the graph of the f(X) cuts the X or Y axis i.e. Y=0 or X=0 respectively.
b) (I) y=3x-2( putting X=0)
(0,-2)
(II) y=3x-2 (putting Y=0)
(2/3, 0)
c) (I)y= 3* 0.3-2= -1.1
(II) y=3*0.7-2= 0.1
Answer:
I belive its C. Group members provide social support
Explanation:
Because group therapy is where people with the same problems get together and share their problems almost like Alcholic Anonymous.
Answer:
Explanation:
Part D
For d, the very first thing you need to do is figure out which one of the steps you are going to use. You have 2 in b^2 + 2, so even if b = 0 the two still matters. It means that you use f(x) = -x + 3 because that's what you use when you have 2 or above.
The second thing you have to realize is that f(x) = -x + 3 has the meaning of what ever you see on the left in the place of x, you put on the right wherever there is an x.
In this case f(b^2 + 2) = -b^2 - 2 + 3 = 1 - b^2
I'm not sure enough to give you an answer for the domain and range, not this time of night.
