Answer:
The probability that a randomly selected call time will be less than 30 seconds is 0.7443.
Step-by-step explanation:
We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.
Let X = caller times at a customer service center
The probability distribution (pdf) of the exponential distribution is given by;

Here,
= exponential parameter
Now, the mean of the exponential distribution is given by;
Mean =
So,
⇒
SO, X ~ Exp(
)
To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;
; x > 0
Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)
P(X < 30) =
= 1 - 0.2557
= 0.7443
Can you show us the triangular prism to help you
Well based on this information, I don't think that this is a valid inference. There isn't enough data to go off of in order to answer this question.
Answer: 5.22kg
Step-by-step explanation:
From the question, a farmer sells 8.7 kilograms of pears and apples at the market. Of the pears and apples sold, 2/5 of this weight is pears, and the rest is apples. To calculate the kilograms of apple sold goes thus:
Total kilograms sold = 8.7kg
Fraction of pears weight = 2/5
Pears kilograms sold = 2/5 × 8.7
= 0.4 × 8.7
= 3.48kg
Since the kilograms of pears sold is , 3.48kg, to get the kilograms of apple sold, we subtract 3.48kg from 8.7kg. This will be:
= 8.7kg - 3.48kg
= 5.22kg
Answer:
Step-by-step explanation:
<u>Given equation:</u>
.
.
<u>Your answer will be Option D.</u>