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Doss [256]
3 years ago
14

When you graph a system of two linear equations, which outcome is NOT possible?

Mathematics
1 answer:
34kurt3 years ago
4 0
Lines cannot intersect at multiple points...so the answer would have to be C :)
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Question 7: 10 pts
Natalija [7]

Answer:

3 divid by 10 is 3 so i guses you have a 3 percent chance at getteing a green marebel

Step-by-step explanation:

6 0
3 years ago
A man weighing 800 N is hanging from a 2 mm diameter titanium wire with a cross-section of 3 x 10^-6 m^2. Will the wire break?
DENIUS [597]

Answer:

Since stress is greater than ultimate strength, the wire will break.

Step-by-step explanation:

The titanium wire is experimenting an axial load. Ultimate strength equals 2.20\times 10^{8}\,Pa. The wire shall break if and only if stress is at least equal to ultimate strength. The equation for axial stress (\sigma), measured in pascals, in the wire with circular cross-section is:

\sigma = \frac{4\cdot F}{\pi\cdot D^{2}} (1)

Where:

F - Axial force, measured in newtons.

D - Cross-section diameter, measured in meters.

Please notice that axial force is the weight of the man hanging from wire.

If we know that F = 800\,N and D = 0.002\,m, then the axial stress experimented by the titanium wire is:

\sigma = \frac{4\cdot (800\,N)}{\pi\cdot (0.002\,m)^{2}}

\sigma \approx 2.546\times 10^{8}\,Pa

Since stress is greater than ultimate strength, the wire will break.

3 0
3 years ago
Which equation has non real solutions
Nutka1998 [239]

Answer:

D.

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
The cost, C dollars, of hiring a taxi is given by the formula C=2.00+320n, where n is the number of tenths of a mile driven. Wha
Ainat [17]

Answer:

$14.80

Step-by-step explanation:

I'm assuming you meant to put 3.20 since $320 a mile would be ridiculous.

C(n)=2.00+3.20n

If n = 4 miles we have:

C(4)=2+3.20(4)

C(4)=2+12.80

C(4)=14.80

So the cost of the taxi is $14.80.

8 0
3 years ago
Help me solve this statistics question please!!
Leni [432]

It's B, D, and E.

Hope ok. :)

7 0
3 years ago
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