<span>54*8+6+14
Multiply 54 by 8
432 + 6 + 14
Add 6 to 432
438+14
Add
Final Answer: 452
</span>
Answer: A 24 cm piece of string is cut into two pieces , one piece is used to form a circle and the other piece is used to form a square.
How should this string be cut so that the sum of the areas is a minimum .
:
Let x = the circumference of the circle
then
(24-x) = the perimeter of the square
:
Find the area of the circle
find r
2*pi*r = x
r =
Find the area of the circle
A =
A =
A = sq/cm, the area of the circle
:
Find the area of the square
A = sq/cm the area of the square
The total area
At = +
Graph this equation, find the min
Min occurs when x=10.6 cm
cut string 10.6 cm from one end
Step-by-step explanation: Hope I help out alot (-: :-)
First you have to solve both inequalities,
3x-1>8
3x>9
x>3
and the other one
2x≤4
x≤2
then you graph each one on the number line
the graph says or, so the solution can satisfy either equation
the solution would be all real numbers except three
the way to write it is x≠3
Answer: 29
Step-by-step explanation:
Let the smaller number be x
Let the bigger number be x+2
The information given in the question can be represented in a equation as:
x + 2 + 2x = 4x - 27
3x + 2 = 4x - 27
4x - 3x = 27 + 2
x = 29
The smaller number is 29
It is isosceles trapezium, so angle A=angle B,
angle C=angle D=angle BDC
triangle BCD,
180=22 +D+(D-88)
(D-88) because in trapezium C=D, angle BCD=ACD-88 or C-88, and D-88
180=2D-66
2D=180+66
2D=246
D=123
