Answer:
The replication (exact duplication) of DNA begins with the unwinding of the double helix.
Explanation:
DNA replication is the first step of the central dogma of molecular biology which deals with the formation of 2 daughter DNA molecules from a single parental DNA.
The replcation begin with unwinding of DNA double helix by the breakage of hydrogen bonds between the complementary base pairs resulting in the formation of replication fork.
This incident occur by the catalytic activity of Helicase or dna B protein.
The main difference in structures between human’s and cat’s liver are lobes.
<span>The cat’s liver consists of six lobe sand those are the left lateral, left medial, right medial, right lateral, caudate and quadrate lobes. On the other hand, a human liver has only four lobes, which are the right, left, caudate and quadrate lobes.</span>
Answer:
no because not all humans are the same. We are all different.
Explanation:
<u>Answer:</u>
Great amounts of energy are released in the core of a star as lighter elements combine and form heavier elements during the process of nuclear fusion.
<u>Explanation:</u>
- Nuclear fusion is the defined as the fusion or combination of many lighter elements to form heavier element.
- Example: Two hydrogen nuclei combine or fuse to form a helium. The greatest amount of energy in star is its hydrogen which gets exhausted consequently resulting in burning of helium and forming heavier elements.
Answer:
C. "Because you have had one child with Tay-Sachs, you must each carry the allele. Any child you have has a 25% chance of having the disease
Explanation:
Tay-Sachs disease is an autosomal recessive disorder that means a child will acquire the phenotype or we can say disease only when both the alleles which cause disease are present in the child.
Here, in this condition neither parent has Tay-Sachs but they gave birth to a child who is suffering from the disease then it simply means that both the parents are carrier of this disease i.e. they both are heterozygous.
The cross and probability of healthy and diseased child is shown as under:
Mother Father
Parents Tt Tt
/ | | \
Off-springs TT Tt Tt tt
<u>Out of these 4 probable off-springs only 3 with genotype TT, Tt & Tt will be healthy while the 1 with genotype tt will be diseased.</u><u> </u><u>So, the probability of diseased child is 1/4 which is 25%. </u>
Also, the birth of children is an independent event so if one child has already been born with this disease then it doesn't mean that the next 3 children will be healthy for sure i.e. birth of first child cannot influence the next child. In short we can also say that in the next birth, there is still 25% chance of the child being born with this disease because previous birth has nothing to do with next birth.
