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irakobra [83]
3 years ago
15

Find the sum

0%29%20%2B%20%28%20-%20%20%7B5xy%7D%5E%7B2%7D%20%20-%202xy%20%2B%203%29" id="TexFormula1" title="(4 {xy}^{2} - {3x}^{2}y - 5xy - 6 ) + ( - {5xy}^{2} - 2xy + 3)" alt="(4 {xy}^{2} - {3x}^{2}y - 5xy - 6 ) + ( - {5xy}^{2} - 2xy + 3)" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Lera25 [3.4K]3 years ago
7 0

Answer:

-3x^2y-xy^2-7xy-3

Step-by-step explanation:

(4xy^2-3x^2y-5xy-6)+(-5xy^2-2xy+3)

4xy^2-3x^2y-5xy-6-5xy^2-2xy+3

-3x^2y-xy^2-7xy-3

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1/3× 21/4-11/2÷22/5?? .btw they are improper fractions​
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<h3>Solution:</h3>

\frac{1}{3}  \times  \frac{21}{4}  -  \frac{11}{2}  \div  \frac{22}{5}  \\  =  \frac{1}{3}  \times  \frac{21}{4}  -  \frac{11}{2}  \times  \frac{5}{22}  \\  =  \frac{1}{3}  \times  \frac{21}{4}  -  \frac{5}{4}  \\  =  \frac{7}{4}  -  \frac{5}{4}  \\  =  \frac{2}{4}  \\  =  \frac{1}{2}

<h3>Answer:</h3>

\frac{1}{2}

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