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3 years ago

Anyone know this i cant figure it out

Mathematics

1 answer:

allochka39001 [22]3 years ago

7 0

Answer:

True False True

Step-by-step explanation:

1. A circle has 360 degrees in its interior. 360 - 130 (this is given) degrees = 230 degrees. This means it's TRUE

2. The area of the shaded sector is the degrees in the central angle that contains the sector, multiplied by the area of the circle. This means that the area is pi*r^2*angle. The radius is 10, and the angle is 230 degrees, so the answer is 100*230/360 pi = 23000/360 pi, which simplifies to 575/9 pi. This is FALSE.

3. The area of the shaded sector is area of the circle - area of the shaded sector. The area of the circle is pi r^2, which is 100 pi. 100 pi - 575/9 pi = 325pi/9, so this is TRUE

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Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

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Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$