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NARA [144]
3 years ago
5

Jasmine made a scale drawing of the cafeteria. The scale used was 1 inch = 5 feet. If the gym is 24 inches by 32 inches in the d

rawing, what is the area of the actual gym?
Mathematics
1 answer:
serious [3.7K]3 years ago
6 0

Answer:

19,200 square feet.

Step-by-step explanation:

We have been given that Jasmine made a scale drawing of the cafeteria. The scale used was 1 inch = 5 feet.

The dimensions of gym are 24 inches by 32 inches.

Let us find the actual dimensions of gym by multiplying length and width of the scale drawing of gym by 5.

\text{Actual length of gym}=24\text{ inches}\times\frac{ 5\text{ feet}}{\text{inch}}

\text{Actual length of gym}=24\times 5\text{ feet}

\text{Actual length of gym}=120\text{ feet}

\text{Actual width of gym}=32\text{ inches}\times\frac{ 5\text{ feet}}{\text{inch}}

\text{Actual width of gym}=32\times 5\text{ feet}

\text{Actual width of gym}=160\text{ feet}

Let us find the area of actual gym by multiplying its actual length with actual width.

\text{Area of the actual gym}=120\text{ feet}\times 160\text{ feet}

\text{Area of the actual gym}=19200\text{ feet}^2

Therefore, the area of the actual gym is 19,200 square feet.

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