1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2
-3+7=4 should be your answer
Answer:
they need to be in ratios format
Step-by-step explanation:
Answer:
Step-by-step explanation:
In a dilatation for find the new coordinates we have to multiply the initial value for the the scale factor
A’(-3, 12)
B’(9,6)
C’(-9,-3)
so the general rule is:
(x,y) -> (3x, 3y)
Answer:
y + 2 = -2(x - 3)^2
Step-by-step explanation:
We can see immediately that the vertex is at (3, -2).
The vertex form of the equation of a parabola is
y - k = a(x - h)^2.
If the parabola opened upward, the equation would be y + 2 = 2(x - 3)^2. But seeing that this particular parabola opens downward, the equation is
y + 2 = -2(x - 3)^2.
Check: Does the point (2, -4) satisfy this equation?
-4 + 2 = -2(2 - 3)^2 becomes -2 = -2(-1)^2, which is true.
