Answer: cost of 1 pot of ivy = $12
Cost of 1 rose bush =$ 10
Step-by-step explanation:
Step 1
Let rose bushes be represented as r
and pot of ivy be represented as p
such that Amy who spent 82 dollars on 7 rose bushes and 1 pot of ivy can be expressed as
7 r + p = 82----- eqn 1
Rob who spent 74 on 5 rose bushes and 2 pots of ivy can be expressed as
5r +2 p = 74----- eqn 2
Step 2
Solving
7 r + p = 82----- eqn 1
5r +2 p = 74----- eqn 2
By elimination method Multiply eqn 1 by 5 and eqn 2 by 7
35r+ 5p= 410--- eqn 3
35r+ 14p =518--- eqn 4
Subtracting eqn 4 from eqn 3
9p = 108
p = 108/9
p=12
p = pot of ivy = $12
therefore rose bush wll be ( from equation 1)
7r+ p= 82
7r=82-12
7r= 70 r= 70/7
r= rose bush =$ 10
The correct answer is B i think hope you get it right!!
The answer would be : 18.0
Hope this helps !
Photon
The triangles are similar by the AA similarity theorem, therefore, the answer is: (b) yes, because ∠QUR ≅ ∠TUS (vertical angles) and ∠r ≅ ∠s (alternate interior angles).
<h3>What is the AA Similarity Theorem?</h3>
If two angles in one triangle are said to be the same or congruent to two corresponding angles in another triangle, based on the AA similarity theorem, the two triangles can be proven to be similar triangles.
In the diagram given, we know that: angles QUR is congruent to angle TUS based on the vertical angles theorem.
We also known that, alternate interior angles, angles R and S are congruent.
This means that both triangles have two pairs of corresponding congruent angles. We can prove that they are similar to each other by the AA similarity theorem, therefore, the answer is: (b) yes, because ∠qur ≅ ∠tus (vertical angles) and ∠r ≅ ∠s (alternate interior angles).
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The area of square fabric piece is 10.24 cm^2
Step-by-step explanation:
Square is a four-sided shape where all sides are equal. The area of square is calculated by using its side.
Given
Side length of fabric piece = s = 3.2 cm
The area of square is given by:
Putting s= 3.2
Hence,
The area of square fabric piece is 10.24 cm^2
Keywords: Square, area
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