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4 years ago

5

[please help I’ve been stuck on this for hours :(] David made a scale drawing of his basketball goal. The basketball is 15 feet

tall. In the drawing the basketball goal is 3 inches. What is the scale of drawing?

2 answers:

nydimaria [60]4 years ago

7 0

Answer:5

Step-by-step explanation:

I said that because I just divide

o-na [289]4 years ago

5 0

Answer:

5 inches? i thinK?

Step-by-step explanation:

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450

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2 years ago

Sharlene opened a new account and deposited $6,000.

allsm [11]

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3 years ago

Brett has a $30 online gift voucher. He plans to buy as many books as he can . The cost of each book is $4. There is also a sing

Mrac [35]

Answer:

7

Step-by-step explanation:

30 >or equal to 4x + 2

Solve for x

28 > or equal to 4x

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5 0

4 years ago

Alyssa worked 2 part-time jobs and earned $181.50 for working a total of 24 hours at both jobs. She is paid $6.00 per hour at jo

jeka57 [31]

Answer:

Alyssa work at job A $9\ hours$

Step-by-step explanation:

Let

x------> the number of hours at work A

y------> the number of hours at work B

we know that

$x+y=24$

$y=24-x$ -----> equation A

$6x+8.5y=181.5$ -----> equation B

substitute equation A in equation B

$6x+8.5(24-x)=181.5$

$6x+204-8.5x=181.5$

$8.5x-6x=204-181.5$

$2.5x=22.5$

$x=22.5/2.5$

$x=9\ hours$

5 0

3 years ago

You would like to know whether forwards in a basketball league average the same (or different) numbers of points than the overal

Akimi4 [234]

Answer:

The critical t-value for such a test given an alpha level of 0.05 is 2.26

Step-by-step explanation:

Null hypothesis : $H_0:\mu = 7.5$

Alternate hypothesis : $H_a:\mu \neq 7.5$

Population mean = $\mu = 7.5$

Data : 10, 9, 6, 11, 13, 14, 9, 9, 9, and 10

Mean = $\bar{x}=\frac{\text{Sum of all observations}}{\text{no. of observations}}$

Mean = $\frac{10+9+6+11+13+14+9+9+ 9+ 10}{10}$

Mean =10

Standard deviation : $\sqrt{\frac{\sum(x-\bar{x})^2}{n}}$

Standard deviation : $\sqrt{\frac{(10-10)^2+(9-10)^2+(6-10)^2+(11-10)^2+(13-10)^2+(14-10)^2+(9-10)^2+(9-10)^2+(9-10)^2+(10-10)^2}{10}}$

Standard deviation s :2.144

$t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}t = \frac{10-7.5}{\frac{2.144}{\sqrt{10}}}t=3.687$

Df = n-1 = 10-1 = 9

T critical = $t_{(df,\alpha)}=t_(9,0.05)=2.26$

T calculated > T critical

So, We failed to accept null hypothesis

Hence the critical t-value for such a test given an alpha level of 0.05 is 2.26

5 0

3 years ago