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2 years ago

Can someone help me please?

Mathematics

2 answers:

Olenka [21]2 years ago

6 0

Answer:

sin ∠I = 12/13

Step-by-step explanation:

SOH CAH TOA

↑ sin = opposite side/hypotenuse

sin ∠I = 48/52 => sin ∠I = 12/13

netineya [11]2 years ago

5 0

The answer is =12/13z

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1. Sarah applies the pearl guitar fret markers to her fret board as shown. Each fret marker is in the shape of a parallelogram.

Flura [38]

Answer:

315

Step-by-step explanation:

We are told in the question that each fret marker is in the shape of a parallelogram

The area of a parallelogram is given as

Base × Height.

Each of the bottoms of the fret markers has the following values

Base = 52.5mm

Height =6 mm

The area of each of the bottom fret markers

= Base × Height

= 52.5 × 6

= 315

Therefore, the area of each of the bottom fret markers without unit is 315

7 0

3 years ago

Triangle congruence... SAS SSS AAS ASA pls explain why

abruzzese [7]

Answer:

it is SAS

Step-by-step explanation:

because BC is common side in both triangles

now two triangles have 2 sides equal and 1 angle equal so

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2 years ago

I will use fancy gold and red wrapping paper for two packages i have to wrap. I will use 1 2/4 yard of paper for one of the boxe

Allisa [31]

Well you need first 1 2/4 of a yard. Then you will need 5/6 of a yard. But first you need to put them together. So we need to find the common denominator. Six and four both share which multiple? Twelve. So let's rewrite that. You need 1 6/12 yards + 10/12 yards of wrapping paper. But before we do anything else we need to fix the mixed number. 1 6/12 isn't as easy to add ad 18/12 is. So 18/12 + 10/12 = 28/12
That can simplify as well. Now it's 14/6 which is equivalent to the fraction we had before. But it can also go down to 2 2/6. Now we can simplify it even further. By dividing it by two we can get 2 1/3. These are the measurements we need. So you would need how many thirds? Seven. (2 1/3 is seven thirds) This is your final answer.

You would need to have seven peices of wrapping paper cut to wrap both gift boxes.

6 0

3 years ago

A circle is shown. Secants S V and T V intersect at point V outside of the circle. Secant S V intersects the circle at point W.

Marat540 [252]

Given:

Secants S V and T V intersect at point V outside of the circle. Secant S V intersects the circle at point W. Secant T V intersects the circle at point U.

The length of TU is (y - 2).

The length of UV is 8.

The length of SW is (y + 4)

The length of WV is 6.

We need to determine the length of line segment SV.

Value of y:

The value of y can be determined using the intersecting secant theorem.

Applying, the theorem, we get;

$WV \times SV=UV \times TV$