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IceJOKER [234]
3 years ago
14

GIVING OUT 5 POINTS JUST ANWSER THIS QUESTION 2+6 TIMES 3000001 DIVIDED BY 23 AND SUBTRACT 2 AND ADD 1

Mathematics
1 answer:
Maurinko [17]3 years ago
3 0

Answer:

\frac{23913}{25000}

Step-by-step explanation:

According to the Order of Operations [GEMS\BOMDAS\PEMDAS etc.], Subtraction & Addition are evaluated after Division & Multiplication:

2 + 6 \times 3000001 \div 23 - 2 + 1 \\  \\ 2 + 782608\frac{1913}{2000} - 2 + 1 = \frac{23913}{25000}

I am joyous to assist you anytime.

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Amelia recorded the heights, in centimeters, and ages, in weeks, of pepper plants in her garden.
baherus [9]
Equation: y=4x+6

When x = 1
y=4(1)+6
y=4+6
y=10

When x=3
y=4(3)+6
y=12+6
y=18

and so on........
Use non-negative integers as your range (1,2,3,4,5)

Plot your graph

8 0
3 years ago
SOMEONE HELP PLSS!! ILL BE GIVING BRAINLIEST AND ILL ALSO BE GIVING AWAY EXTRA POINTS
Korolek [52]

Answer:

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Step-by-step explanation:

5 0
3 years ago
The tree diagram below shows all of the possible outcomes for flipping three coins.
creativ13 [48]

The probability that two of the coins will be tails is 1/2

It is 1/2 because "at least two tails" means that two tails and the rest of the number of tails, which is 3. In total the three coins have 6 sides. The chance of having two tails and one is three out of 6, simplified is 1/2 ;)

8 0
4 years ago
Read 2 more answers
Jharana got Rs.1881 interest of certain sum for 2year at 9% compounded yearly.find the sum.​
Lana71 [14]

The principal sum is Rs.10,000

Step-by-step explanation:

The formula of compound interest is:

I=P(1+\frac{r}{n})^{nt}-P where:

  • I is the interest
  • P is the principal investment amount (the initial deposit or loan amount)
  • r is the annual interest rate (decimal)
  • n is the number of times that interest is compounded per unit t
  • t is the time the money is invested or borrowed for

Jharana got Rs.1881 interest of certain sum for 2 year at 9%

compounded yearly

∵ I = Rs.1881

∵ r = (9/100) = 0.09

∵ n = 1 ⇒ compounded yearly

∵ t = 2 years

Substitute all of these values in the rule above

∴ 1881=P(1+\frac{0.09}{1})^{(1)(2)}-P

∴ 1881 = P(1 + 0.09)² - P

∴ 1881 = P(1.09)² - P

∴ 1881 = 1.1881 P - P

∴ 1881 = 0.1881 P

- Divide both sides by 0.1881

∴ P = 10,000

The principal sum is Rs.10,000

Learn more:

You can learn more about the interest in brainly.com/question/11149751

#LearnwithBrainly

3 0
3 years ago
Suppose that a company has just purchased a new computer for $1500 The company chooses to depreciate using the straight-line met
agasfer [191]

<u>Solution-</u>

The company purchased a new computer for $1500 and chooses to depreciate using the straight-line method for 5 years.

a-

As the value is depreciating, so its slope will be -ve.

Slope =- \frac{1500}{5}=-300 ( ∵ The value of 1500 will depreciate in 5 years )

y-intercept = 1500           ( ∵ At the beginning when x=0, y=1500)

Linear equation of the system,

y = mx +c ,

where,

m = slope = -300,

c = y-intercept = 1500

Putting the values,

y=-300x+1500

\Rightarrow y=1500-300x


b-

The implied domain of the function is 1≤x≤5 or [1,5]


c-

Follow the attachment attached herewith for the graph.


d-

Here,

y = the value of the computer

.

x = number of years depreciated = 3

Putting the values in the linear equation,

y = 1500-300(3) = 1500-900 = 600

∴  The book value of the computer after 3 years is $600.


e-

Here given that,

y = value of computer = 1600

x = asked = ??

Putting the values in the equation,

1600 = 1500 - 300x

⇒ 100= -300x

⇒ x= -3

∴ As the x is in negative, i.e it is impossible for the computer to be worth of 1600. It happens also because as the value is depreciating, it will always be less than 1500.



3 0
3 years ago
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