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Eduardwww [97]
3 years ago
10

Midpoint and distance formula zombie worksheet

Mathematics
1 answer:
Strike441 [17]3 years ago
3 0

Consider two points in a two dimensional coordinate plane

(x_{1},y_{1})\text { and }  (x_{2},y_{2})

As you know mid point of a line joining two points is the coordinate of the middle point of only that portion of line joining between two points.

[tex]\text   { Mid point of  }  (x_{1},y_{1})\text { and }  (x_{2},y_{2}) =(\frac{x_{1}+x_{2}}{2} ,\frac{y_{1}+y_{2}}{2})[/tex]

As we know distance formula gives the Distance between line joining two points in two dimensional coordinate system.It is always positive.

[tex]\text   { Distance formula between two points  }  (x_{1},y_{1})\text { and }  (x_{2},y_{2}) =\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}[/tex]

Distance formula gives the distance between two points, whereas Mid point formula gives coordinate of the middle point.

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Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y
professor190 [17]

Answer:

Required total charge is 256\pi coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

x^2=y^2\leq 16 so that the charge density at (x,y) is,

\rho (x,y)=2x+2y+2x^2+2y^2

To find total charge on the disk let Q be the total charge and x=r\cos\theta,y=r\sin\theta so that,

Q={\int\int}_Q\rho(x,y) dA                where A is the surface of disk.

=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA

=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta

=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta

=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta

=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta

=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi

=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi

=256\pi

Hence total charge is 256\pi coulombs per square meter.

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3 years ago
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