Consider two points in a two dimensional coordinate plane
As you know mid point of a line joining two points is the coordinate of the middle point of only that portion of line joining between two points.
[tex]\text { Mid point of } (x_{1},y_{1})\text { and } (x_{2},y_{2}) =(\frac{x_{1}+x_{2}}{2} ,\frac{y_{1}+y_{2}}{2})[/tex]
As we know distance formula gives the Distance between line joining two points in two dimensional coordinate system.It is always positive.
[tex]\text { Distance formula between two points } (x_{1},y_{1})\text { and } (x_{2},y_{2}) =\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}[/tex]
Distance formula gives the distance between two points, whereas Mid point formula gives coordinate of the middle point.
Answer:
Option C is correct
The coordinate of C' or the transformed point of C is (-6, 5)
Step-by-step explanation:
From the given graph:
In triangle ABC:
Coordinate of C is:
C(-3, 4)
The rule of transformation is given:
We have to find the coordinate of C'.
Apply the transformation on coordinate C:
Therefore, the coordinate of C' is (-6, 5)
Answer:
The length of KH is 6 units and OH is 6.3 units.
Step-by-step explanation:
Given the figure with lengths LO=5 and OK=4. we have to find the length of OH and KH.
In ΔLOH
By Pythagoras theorem
→ (1)
In ΔKOH,
→ (2)
In ΔKHL,
Using eq (1) and (2), we get
⇒
⇒
Put the above value in eq 2, we get
⇒ KH=6 units.