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ExtremeBDS [4]
3 years ago
9

115>5.75x+28.75 what is x

Mathematics
1 answer:
julsineya [31]3 years ago
4 0
115>5.75x+28.75
5.75x+28.75<115
5.75x<115-28.75
5.75x<86.25
x<86.25/5.75
x<15       or (-∞,15)

Answer: x<15      or        (-∞,15)
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The product of 4 and the sum of a number x and 8
Mademuasel [1]

Answer:

4(x+8)

Step-by-step explanation:

hope this helps

Then if you want to know the value of x.

This is the solution 4(x+8)

4x+32 to find the x divide both by side by 4.

4x/4+32/4

x=8

7 0
3 years ago
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A 0.143-Henry Inductor is connected in series with a variable resistor to a 208-volt 400-cycle source. For what value of capacit
aleksandr82 [10.1K]

Answer:

A.)359.2, B.)2.5 uf

Step-by-step explanation:

E / I = R

208 / 1.04 = 200 ohms

2*pi*f*L = Xl

6.28*400*.143 = 359.2 ohm

1 / (2*pi*f*Xc) = c

1 /(6.28*400*159.2) = 2.5 uf

8 0
3 years ago
How do u put 72 7/10 into decimal?
NNADVOKAT [17]

Answer:

72.7

Step-by-step explanation:

First multiply 72 by 10

because 72 is 72 10s, making it a whole number.

then add 720 (72 times 10) to 7.

then all of that over 10.

then just divide.

727/10

72.7

this is what you do for all mixed numbers like that one.

7 0
3 years ago
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A regular hexagon has an area of 750.8 cm. The side length is 17 cm. Find the apothem.
kompoz [17]

Since, a regular hexagon has an area of 750.8 square cm and The side length is 17 cm.

We have to find the apothem of the regular hexagon.

The formula for determining the apothem of regular hexagon is s \div {{2 \tan (\frac{180}{n})}, where 's' is any side length of regular hexagon and 'n' is the number of sides of regular hexagon.

So, apothem = 17 \div {2 tan(\frac{180}{6})

= 17 \div {2 tan(30)

= 17 \div {1.15}

= 14.78 units

Therefore, the measure of apothem of the regular hexagon is 14.7 units.

Option B is the correct answer.

5 0
3 years ago
28 students in the class 75% pass how many students pass
SashulF [63]

Answer:

21 students pass

Step-by-step explanation:

Firstly, you can set up the problem into an equation where the variable X would equal the number of students passing. You put X over the total number of students in the class, turning it into a fraction, then set it equal to the fraction  \frac{75}{100} (which is 75% represented as a fraction).

\frac{X}{28} = \frac{75}{100}

The fraction \frac{75}{100} can be simplified, because 75 and 100 are both multiples of 25, so after canceling out the 25s you would be left with \frac{3}{4}.

\frac{X}{28} = \frac{3}{4}

Next, you use the process of cross multiplication which is essentially just multiplying the denominators of both fractions (which would be 28 and 4 in this case) to each side of the equation.

\frac{X}{28} * 28 * 4 = \frac{3}{4} * 4 * 28

The denominators cancel out leaving you with a simple equation to simplify.

4* X =  3 * 28

4X = 84

Finally, divide both sides by four in order to isolate the variable.

\frac{4X}{4} = \frac{84}{4}

X = 21.

5 0
3 years ago
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