Answer:
Step-by-step explanation:
1). m∠AEC = m∠AEB + m∠BEC
= 21° + 37°
= 58°
2). m∠BED = m∠BEC + m∠CED
= 37° + 44°
= 81°
3). m∠IKF = m∠IKH + m∠HKG + m∠GKF
= m∠IKH + m∠HKG + m∠IKH [Since, ∠IKH ≅ ∠GKF]
= 2∠IKH + m∠HKG
103° = 2∠IKH + 41°
2(∠IKH) = 103 - 41
m(∠IKH) = 31°
4). m∠AED = m∠AEB + m∠BEC + m∠CED
= 21° + 37° + 44°
= 102°
5). m∠JKG = 108°
m∠JKG = m∠JKI + m∠IKH + m∠HKG
108° = m∠JKI + 31° + 41°
m∠JKI = 108° - 72°
m∠JKI = 36°
6). m∠HKF = m∠GKF + m∠HKG
= m∠IKH + m∠HKG [Since, m∠GKF = m∠IKH]
= 31° + 41°
= 72°
7). m∠NQO = m∠MQN = 64°
8). m∠JKF = m∠JKI + m∠IKF
= 36° + 103°
= 139°
8). m∠MQO = 2(m∠NQO)
= 2(64)°
= 128°
9). m∠LQO = 156°
m∠LQM = m∠LQO - m∠MQO
= 156° - 128°
= 28°
10. m∠NQP = m∠NQO + m∠OQP
= 64° + m∠LQM [Since ∠OQP ≅ ∠LQM]
= 64° + 28°
= 92°
Yes because if you find common denominators (in this case, "10") you would have to compare 8/10 to 5/10. 8>5 so 8/10 is longer than 1/2.
Answer:
first number= 19/5
second number= 2/5
Step-by-step explanation:
first number= a
second number= b
a+3b=5 equation 1
b+2a=8 equation 2
using equation 2 we have
b=8-2a
using equation 1 we have
a+3(8-2a)=5
a+24-6a=5
24-5=6a-a
19=5a
a=19/5 = first number
so using b=8-2a
we have
b=8-2(19/5)
b=8-(38/5)
b=2/5 = second number
Answer:
Look down below!
Step-by-step explanation:
Fist, make your inequality:
-x + 5y > -10
5y > x - 10
y = .2x - 2
Now, plug in any value of x to find y!
Ex: x = 5...
y = .2 (5) - 2
y = -1
Your first coordinate could be (5, -1)
Hope this helps!
Answer:
Repeating decimal
Step-by-step explanation:
The bar over any number to the right of a decimal point denotes that the number is recurring. Meaning that if the bar (line) is over the number 3 in 0.3, the number 3 is being repeated infinitely. (0.333333333333333333....)
These types of decimals are known as repeating or recurring decimals.
Hope this helps!
