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AleksAgata [21]
3 years ago
10

Alena had 4 packs of gum with 6 pieces of gum in each pack. Hugh had 3 packs of gum with 5 pieces in each. Alena and Hugh have 1

9 pieces of gum left. Which equation can you use to find p, the number of pieces of gum Alena and Hugh chewed?
A) 19-(4•6)+(3•5)=p
B) (4•6)+(3•5)-19=p
C) 19-(3+4)•(6+5)=p
Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
6 0
I believe it’s b I might be wrong tho
dybincka [34]3 years ago
3 0

Answer:

B) ( 4 * 6 ) + ( 3 * 5 ) - 19

Step-by-step explanation:

As per the given information

Alena - has a total of 4 packs of gum, with 6 pieces each

          - so she has a total of  4 * 6 = 24

Hugh - has a total of 3 packs of gum, with 5 pieces each

         - so he has a total of 3 * 5 = 15

Add the two of them up to find the total amount of gum they have

Alena + Hugh

= ( 4 * 6 ) + ( 3 * 5 )

They have 19 pieces left

So the total amount they have, minus 19 will yield the amount they chewed.

Hence:

Alena + Hugh -19

= ( 4 * 6 ) + ( 3 * 5 ) - 19

That is option B

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Can you guys help please im so confused
marissa [1.9K]

Answer:

a) see below

b) 40x20 meters

Step-by-step explanation:

Write down what you know:

- The area of the enclosure is length*width, so

A = x \cdot y

- The length of the fencing is 80 meters, so

2y + x = 80

Now we have to combine these two equations above, and get rid of y in the process.

First rewrite the second as:

y = 40 - \frac12 x

Then substitute for y in the first:

A = x (40 - \frac12 x) = 40x - \frac12x^2

b) To maximize A, find the zero of the first derivative:

A'(x) = 40 - x = 0 \implies x=40

So y = (80-40)/2 = 20 meters.

8 0
2 years ago
A fitted multiple regression equation is Y = 28 + 5X1 - 4X2 + 7X3 + 2X4. When X1 increases 2 units and X2 increases 2 units as w
ad-work [718]

Answer:

A. Increase by 2

Step-by-step explanation:

Given that a  fitted multiple regression equation is

Y = 28 + 5X_1 -4X_2 + 7X_3 + 2X_4

This is a multiple regression line with dependent variable y and independent variables x1, x2, x3 and x4

The coefficients of independent variables represent the slope.

In other words the coefficients represent the rate of change of y when xi is changed by 1 unit.

Given that x3 and x4 remain unchanged and x1 increases by 2 and x2 by 2 units

Since slope of x1 is 5, we find for one unit change in x1 we can have 5 units change in y

i.e. for 2 units change in x1, we expect 10 units change in Y

Similarly for 2 units change in x2, we expect -2(4) units change in Y

Put together we have

10-8 =2 change in y

Since positive 2, there is an increase by 2

A. Increase by 2

5 0
3 years ago
Help because this is dificulty to me
scoray [572]

Answer:

false false true false ez

6 0
3 years ago
5 2/3 divide 4 2/3 equals
Viefleur [7K]

Answer:

1 3/4

Step-by-step explanation:

if you turn it into a inproper fraction it would be 17/3 divide by 14/3 which is 17/14 if you want iy in a mix number its 1 3/14

6 0
3 years ago
A numerical pass code is required to open a car door. The pass code is five digits long and uses the digits 0-9.
topjm [15]

Answer:

100000 pass codes

Step-by-step explanation:

the pass code form is: abcde

a: 10 numbers to choose

b: 10 numbers

c: 10 numbers

d: 10 numbers

e: 10 numbers

so there are 10^5 = 100000 pass codes exist

8 0
3 years ago
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