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AleksAgata [21]
2 years ago
10

Alena had 4 packs of gum with 6 pieces of gum in each pack. Hugh had 3 packs of gum with 5 pieces in each. Alena and Hugh have 1

9 pieces of gum left. Which equation can you use to find p, the number of pieces of gum Alena and Hugh chewed?
A) 19-(4•6)+(3•5)=p
B) (4•6)+(3•5)-19=p
C) 19-(3+4)•(6+5)=p
Mathematics
2 answers:
Thepotemich [5.8K]2 years ago
6 0
I believe it’s b I might be wrong tho
dybincka [34]2 years ago
3 0

Answer:

B) ( 4 * 6 ) + ( 3 * 5 ) - 19

Step-by-step explanation:

As per the given information

Alena - has a total of 4 packs of gum, with 6 pieces each

          - so she has a total of  4 * 6 = 24

Hugh - has a total of 3 packs of gum, with 5 pieces each

         - so he has a total of 3 * 5 = 15

Add the two of them up to find the total amount of gum they have

Alena + Hugh

= ( 4 * 6 ) + ( 3 * 5 )

They have 19 pieces left

So the total amount they have, minus 19 will yield the amount they chewed.

Hence:

Alena + Hugh -19

= ( 4 * 6 ) + ( 3 * 5 ) - 19

That is option B

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Debora [2.8K]

Answer:

6

Step-by-step explanation:

This problem centers on recognizing the relationship between fractions and repeating decimals.

<u></u>

Note the following:

\frac{1}{3}=0.33333333333333333333333333333333333333333333333...  

or more simply \frac{1}{3}=0.\bar{3}

This means that 2\frac{1}{3}=2.\bar{3}

Going back to the original expression, 3\frac{2}{3}+2.\bar{3}  simplifies to 3\frac{2}{3}+2\frac{1}{3}

Next, adding mixed numbers.  For adding mixed numbers, whole number parts and fractional parts can be added separately <em>(this is because of the associative and commutative properties of addition)... because </em>

3\frac{2}{3}+2\frac{1}{3} means the same thing as

(3+\frac{2}{3})+(2+\frac{1}{3})

Changing the order, we can write it as

3+2+\frac{2}{3}+\frac{1}{3}

Adding the whole number parts, 3+2 is 5.

Next, adding the fraction parts:

For adding fractions, one must have a common denominator (the bottom part of the fraction must be the same).  Once they are the same, the denominator just sort of "hangs out" until the end without changing, and the numerators (the tops) are added together.

Fortunately, the denominators are already the same.  So, add the numerators, and the denominator will stay as a 3.

\frac{2}{3}+\frac{1}{3}

\frac{1+2}{3}

\frac{3}{3}

It is important to recognize that any fraction* where the number on the top matches the number on the bottom, the fraction is equivalent to 1.

<em>*(except if the number we're talking about is zero)</em>

So, the fraction parts added together, are equivalent to 1, and the whole number parts added were equal to 5.  Returning to our expression...

3+2+\frac{2}{3}+\frac{1}{3}

5+\frac{3}{3}

5+1

6

7 0
2 years ago
PLEASE HELP I GIVE THANKS
VashaNatasha [74]
It is an obtuse triangle because all of the sides are diffrent amount

5 0
3 years ago
Read 2 more answers
John is expanding these two brackets.
Elan Coil [88]

Answer: Um, the answer is B, and C?

Step-by-step explanation:

5 0
3 years ago
Solve for x.
Nonamiya [84]

-\dfrac{2}{3}(3x-4)+3x=\dfrac{5}{6}\ \ \ \ |\text{use distributive property}\\\\-\dfrac{2}{\not3_1}\cdot\not3^1x+\dfrac{8}{3}+3x=\dfrac{5}{6}\\\\-2x+3x+\dfrac{8}{3}=\dfrac{5}{6}\ \ \ \ |-\dfrac{8}{3}\\\\x=\dfrac{5}{6}-\dfrac{8}{3}\\\\x=\dfrac{5}{6}-\dfrac{8\cdot2}{3\cdot2}\\\\x=\dfrac{5}{6}-\dfrac{16}{6}\\\\\boxed{x=-\dfrac{11}{6}}

Other method:

-\dfrac{2}{3}(3x-4)+3x=\dfrac{5}{6}\ \ \ \ |\cdot6\\\\2(-2)(3x-4)+18x=5\\\\-4(3x-4)+18x=5\ \ \ \ |\text{use distributive property}\\\\-12x+16+18x=5\ \ \ \ |-16\\\\6x=-11\ \ \ \ |:6\\\\\boxed{x=-\dfrac{11}{6}}

7 0
3 years ago
Read 2 more answers
Free fall reaches 216km per hour. What is rate in meters per second.? How many meters fall during 20 seconds free fall?
lakkis [162]

Given,

Rate of free fall = 216 km/h

Solution,

km/h to m/s is converted as follows :

216\ \dfrac{km}{h}=216\times \dfrac{1000\ m}{3600\ s}\\\\=60\ m/s

So, the rate of fall is 60 m/s.

If t = 20 s

Assume, initial velocity = 0

It will move under the action of gravity.

Using equation of motion,

h=ut+\dfrac{1}{2}gt^2\\\\h=0+\dfrac{1}{2}\times 10\times 20^2\\\\h=2000\ m

Hence, this is all for the solution.

4 0
3 years ago
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