Answer:
f(x) = 0.5(x + 3)^2 + 5.
Step-by-step explanation:
The horizontal stretch is given by multiplying by 1/2 or 0.5:
f(x) = 0.5x^2
Now a shift of 3 to the left gives f(x) = 0.5(x + 3)^2.
5 units up gives 0.5(x + 3)^2 + 5.
Exact form: -square root 2/2 (I don't have a square root symbol)
Decimal form: -0.70710678
We have been given that a cosine function is a reflection of its parent function over the x-axis. The amplitude of the function is 11, the vertical shift is 9 units down, and the period of the function is 
. The graph of the function does not show a phase shift. We are asked to write the equation of our function.
We know that general form a cosine function is 
, where,
A = Amplitude,
= Period,
c = Horizontal shift,
d = Vertical shift.
The equation of parent cosine function is 
. Since function is reflected about x-axis, so our function will be 
.
Let us find the value of b.
Upon substituting our given values in general cosine function, we will get:
Therefore, our required function would be .
Answer :
A) 4 and 7 are vertically opposite angles
B) 3 and 6 are alternating angles
C) 6 and 8 are corresponding angles
D) 1 and 8 are exterior alternating angles
This is the right answer :)
