Answer:
Step-by-step explanation:
Hello!
The variable of interest is the readings on thermometers. This variable is normally distributed with mean μ= 0 degrees C and standard deviation σ= 1.00 degrees C.
The objective is to find the readings that are in the top 3.3% of the distribution and the lowest 3.3% of the distribution.
Symbolically:
The lower value P(X≤a)=0.033
Top value P(X≥b)=0.033
(see attachment)
Lower value:
The accumulated probability until "a" is 0.03, since the variable has a normal distribution, to reach the value of temperature that has the lowest 3.3%, you have to work under the standard normal distribution.
First we look the Z value corresponding to 0.033 of probability:
Z= -1.838
Now you reverste the standardization using the formula Z= (a-μ)/δ
a= (Z*δ)+μ
a= (-1.838*1)+0
a= -1.838
Top value:
P(X≥b)=0.033
This value has 0.033 of the distribution above it then 1 - 0.033= 0.967
is below it.
You can rewrite the expression as:
P(X≤b)=0.967
Now you have to look the value of Z that corresponds to 0.967 of accumulated probability:
b= (Z*δ)+μ
b= (1.838*1)+0
b= 1.838
The cutoff values that separates rejected thermometers from the others are -1.838 and 1.838 degrees C.
I hope it helps!
Let the cost of 1 ribeye steak dinner = x
The cost of 1 salmon dinner = y
Then,
11x + 18y = 592.29 (1)
16x + 6y = 580.56 (2)
Multiplying the second equation by 3, we get,
48x + 18y = 1741.68 (3)
(3) - (1) gives
37x = 1149.39
x = 31.06
Substituting the value for x in (1), we get,
11(31.06) + 18y = 592.29
341.66 + 18y = 592.29
18y = 250.63
y = 13.92
Hence, the cost of ribeye steak dinner = 31.06 and the cost of grilled salmon dinner = 13.92.
#sol1
a1=1×4-1=3
a2=2×4-1=7
a3=3×4-1=11
a4=4×4-1=15
a5=5×5-1=19
#sol2
f(1)=1×4-1=3,
f(n+1)=f(n)+4,
so .... you know.
X=7. The two segments on the bottom as well as on the diagonal are the same length. This shows that the entire triangle and the inner triangle on the right are similar. So if we call the length of the bottom 2y, then 84/2y=6x/y. Solving this we get 84=12x, and so x=7