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Stolb23 [73]
3 years ago
11

(011001111)2=(?)10 can anyone solve this urgent Hurry

Computers and Technology
2 answers:
Shtirlitz [24]3 years ago
5 0
You are converting from base 2 to base 10 numeral.

(011001111)_2 =0 \times  {2}^{8}  + 1 \times  {2}^{7}  + 1\times  {2}^{6}  + 0\times {2}^{5}  + 0 \times  {2}^{4}  + 1 \times  {2}^{3}  + 1 \times  {2}^{2}  + 1 \times  {2}^{1}  + 1 \times  {2}^{0}


(011001111)_2 =0 \times  256 + 1 \times 128  + 1\times  64  + 0\times 32  + 0 \times  16  + 1 \times  8  + 1 \times  4  + 1 \times  2  + 1 \times  1

(011001111)_2 =0  + 128  +64  + 0+ 0  + 8  + 4  + 2  +  1
(011001111)_2 =207


frosja888 [35]3 years ago
3 0

207.

In hex, it is 0xCF, which is 12*16+15 = 207

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7 0
3 years ago
Write a function `has_more_zs` to determine which of two strings contains # more instances of the letter "z". It should take as
nekit [7.7K]

Answer:

// Method's name: has_more_zs

// Parameters are text1 and text2 to hold the two phrases to be tested

public static String has_more_zs(String text1, String text2) {

 // Create and initialize z1 to zero

 // Use z1 to count the number of zs in text1

 int z1 = 0;

 // Create and initialize z2 to zero

 // Use z2 to count the number of zs in text2

 int z2 = 0;

 

 //Create a loop to cycle through the characters in text1

 //Increment z1 by one if the current character is a 'z'

 int i = 0;

 while (i < text1.length()) {

  if (text1.charAt(i) == 'z' || text1.charAt(i) == 'Z') {

   z1 += 1;

  }

  i++;

 }

 //Create a loop to cycle through the characters in text2

 //Increment z2 by one if the current character is a 'z'

 

 i = 0; //Re-initialize i to zero

 

 while (i < text2.length()) {

  if (text2.charAt(i) == 'z' || text2.charAt(i) == 'Z') {

   z2 += 1;

  }

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 //Using the values of z1 and z2, return the necessary statements

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  return "The phrase '" + text1 + "'" + " has more occurences of z than the phrase " + "'" + text2 + "'";

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 else if (z1 < z1) {

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 else if (z1 == z2) {

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 }

 else {

  return "Neither string contains the the letter z";

 }

}

Explanation:

Explanation to answer has been given in the code as comments. Please refer to the comments for the details of the code.

The source code file has been attached to this response and saved as "NumberOfZs.java"

Hope this helps!

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Step 7

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