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zysi [14]
3 years ago
14

Simplify 5x + 8y + 4x 17x 9x + 8y 5x + 12y 17xy

Mathematics
1 answer:
antoniya [11.8K]3 years ago
6 0
Combine like terms.

9x + 8y

Hope this helps!
You might be interested in
Please show the working and answer. you can take a picture for the working.
baherus [9]

Answer:

(a) The area of the triangle is approximately 39.0223 cm²

(b) ∠SQR is approximately 55.582°

Step-by-step explanation:

(a) By sin rule, we have;

SQ/(sin(∠SPQ)) = PQ/(sin(∠PSQ)), which gives;

5.4/(sin(52°)) = 6.8/(sin(∠PSQ))

∴ (sin(∠PSQ)) = (6.8/5.4) × (sin(52°)) ≈ 0.9923

∠PSQ = sin⁻¹(0.9923) ≈ 82.88976°

Similarly, we have;

5.4/(sin(52°)) = SP/(sin(180 - 52 - 82.88976))

Where, 180 - 52 - 82.88976 = ∠PQS = 45.11024

SP = 5.4/(sin(52°))×(sin(180 - 52 - 82.88976)) ≈ 4.8549

Given that RS : SP = 2 : 1, we have;

RS = 2 × SP = 2 × 4.8549 ≈ 9.7098

We have by cosine rule, \overline {RQ}² =  \overline {SQ}² +  \overline {SR}² - 2 × \overline {SQ} × \overline {SR} × cos(∠QSR)

∠QSR and ∠PSQ are supplementary angles, therefore;

∠QSR = 180° - ∠PSQ = 180° - 82.88976° = 97.11024°

∠QSR = 97.11024°

Therefore;

\overline {RQ}² =  5.4² +  9.7098² - 2 ×  5.4×9.7098× cos(97.11024)

\overline {RQ}² ≈ 136.42

\overline {RQ} = √(136.42) ≈ 11.6799

The area of the triangle = 1/2 ×\overline {PQ} × \overline {PR} × sin(∠SPQ)

By substituting the values, we have;

1/2 ×\overline {PQ} × \overline {PR} × sin(∠SPQ)

1/2 × 6.8 × (4.8549 + 9.7098) × sin(52°) ≈ 39.0223 cm²

The area of the triangle ≈ 39.0223 cm²

(b) By sin rule, we have;

\overline {RS}/(sin(∠SQR)) = \overline {RQ}/(sin(∠QSR))

By substituting, we have;

9.7098/(sin(∠SQR)) = 11.6799/(sin(97.11024))

sin(∠SQR) = 9.7098/(11.6799/(sin(97.11024))) ≈ 0.82493

∠SQR = sin⁻¹(0.82493) ≈ 55.582°.

8 0
3 years ago
The figure for the other questions
stira [4]
I can't really measure the angles. I can tell you what they look like they'd be. There are three reasons why not. 
1. The paper is slightly bulged where your hand is
2. The circle is slightly distorted by the camera. This  is not that critical. 
3. It is very hard to measure on a computer screen.
There is nothing you could do to make it any better. In fact, given what you had to do, this is a pretty good representation. 

The Three angles -- Question 22
Using the crudest tools you could imagine, I measured the angle where you have written two 90s between the arms as 132°. That angle opens towards the bottom of the page.

The angle that you have called 95 degrees is actually pretty close. I think you read the upper set of numbers on the protractor when you should have been reading the lower set. I make it 89, but I'll bet it is intended to be 90 degrees. 

The third angle on your right is the same as the first one. It comes in at about 132° using my tools again. 

Question 23
I can help you with this. When you are asked to make an equation, you have to use an equal sign somewhere. 

The sum of the three angles should be 360° I'm going to create an error term because I'm almost sure what I measured won't make 360. All circles when you make angles from any point inside them should make angles that add up to 360° when measured with a protractor if the rays of the angles all start from the same point. [If you don't know what a ray is, call it "the arms of the angles"].

So let's create the equation.
Angle1 + angle2 + angle3 + E = 360°
Angle1 = 89° 
Angle2 = 132°
Angle3 = 132°
E is the error that represents the amount away from 360. Your teacher doesn't expect you to get this or to set it into your equation. The main thing you were supposed to do is add up the angles as you tried to do and state what your total was. This is what was expected.
Total = angle1 + angle2 + angle3
Total = 89 + 132 + 132 = 353. My error is 7° too little. So in my equation E = 7°

What to do
Somebody had to mark this with that green felt. You have a teacher. Go to the teacher and ask to be shown how to read the protractor if that person knows. You just need a bit of help. If the teacher cannot tell you, go to someone in your class who knows about that sort of thing and ask them. You're pretty close to getting it.

6 0
3 years ago
Could someone please help, I have been stuck on this for an hour.//
Slav-nsk [51]
I can't answer unless you can provide a picture. Send a pic and I'll help!
4 0
3 years ago
¿Cuál es la ecuación de la recta con pendiente -2 y el punto (4, 10)?
Sophie [7]

The general slope-intercept form equation is:

\begin{gathered} y=mx+b \\ \text{Wher m is the slope and b is the y-intercept value} \end{gathered}

In this case, m=-2 and with the point (4, 10) we can find the value of b:

\begin{gathered} We\text{ evalute the equation in the point (x, y) = (4 , 10):} \\ 10=-2\cdot4+b \\ 10=-8+b \\ b=10+8=18 \end{gathered}

We found that b = 18, so:

y=-2x+18

4 0
1 year ago
Which is equivalent to 216 1/3?<br><br> A.3<br> B.6<br> C.36<br> D.72
nydimaria [60]
The 1/3 power is another way to write the cube root.
  ∛216 = 6
3 0
3 years ago
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