Yes it looks like it but I’m going to try it out
What do you need help with?
Answer:
These lines are perpendicular.
Step-by-step explanation:
Put both equations in the slope intercept form of a line.
y = -6x - 8 This is already in the slope intercept form for a line
-x + 6y = 12 Add x to both sides of the equation
6y = x + 12 Divide through the whole equation by 6
y = 1/6x +2
Now we compare the two slopes of -6 and 1/6. They are negative reciprocals of each other. That means that the line are perpendicular.
Answer:
1.) 6
2.) -1
3.) 36
4.) 1/3
5.) 90
Step-by-step explanation:
1.) -12/a
-12/a -> -12/2
=6
2.) a+ (-b)
a+(-b) -> 2+(-3)
=-1
3.) 3a (12-2b)
3a(12-2b) -> 3(2) (12-2x3)
6(12-6)
6(6)
=36
4.) 2a-c/b
2a-c/b -> 2(2)-5/3
4-5/3
=1/3
5.) 3abc
3abc-> 3x2x3x5
=90
Answer:
2< AC<8
Step-by-step explanation:
For a triangle to exits sum of two sides must always be greater than the the third side
⇒ AC< AB+ BC =5+3=8 in
⇒AC<8 in
Also, the difference of the two sides must be smaller than the length of third side
⇒ AC> | AB-BC| = |5-3| =2
AC> 2 in
therefore, we can say 2< AC<8. Hence, AC can takes 3,4,5,6 values
