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3 years ago

Find the value of the expression (5-3) x 2+6

Mathematics

1 answer:

galben [10]3 years ago

8 0

Answer:

Step-by-step explanation:

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HELP FIRST TO ANSWER ALL IS BRAINLEIST!!!!!!!!!

andreev551 [17]

Answer:

1. D) 1 9/20

2. B) 7/12

4. D) $50.00

Step-by-step explanation:

The working is as follows :

1. Mrs. Lang bought 3/4 pound of red grapes and 7/10 pound of green grapes. To find out how many are in total we have to add both values total.

3/4 + 7/10

The LCM of 4 and 10 is 20.

3/4 * 5 = 15/20

7/10 * 2 = 14/20

15/20 + 14/20 = 29/20 = 1 9/20

2. 1/3 + 1/4

The LCM of 3 and 4 is 12

1/3 * 4 = 4/12

1/4 * 3 = 3/12

4/12 + 3/12 = 7/12

4. Sharon spent 2/3 of her clothing allowance; she was given $75. All we have to do is find 2/3 of $25 :

2/3 * $75 = $50.00

4 0

3 years ago

Create a model to show 2 × 5.

Sliva [168]

Answer:

The model is shown in the attached picture. The solution is 10.

Step-by-step explanation:

There are two way of showing a model for 2×5

The tape diagram has 2 equal-sized parts of 5
The tape diagram has 5 equal-sized parts of 2

Both models give the same solution:

5+5=10
2+2+2+2+2=10

In the attached picture we can show two types of diagram.

5 0

4 years ago

Which fraction is<br> equivalent to 1/8

Law Incorporation [45]

The equivalent fractions are 2/16 8/64

6 0

3 years ago

Read 2 more answers

I need help please i need step by step help

melomori [17]

Mmmmbrntnrjneuneunre unenriched

3 0

3 years ago

Read 2 more answers

You decide to enter in a rowing competition. To train, you go to the boat house and begin rolling down stream. You row for the s

fredd [130]

Answer:

Time spent rowing down stream $=100\ seconds$

Speed of boat in still water $=14\ ms^{-1}$

Step-by-step explanation:

Let speed of boat in still water be $= x\ ms^{-1}$

Speed of current $= 10\ ms^{-1}$

Speed of boat down stream = $\textrm{Speed of boat in still water +Speed of current}= (x+10)\ ms^{-1}$

Distance rowed down stream = 2400 m

Time spent rowing down stream = $\frac{Distance}{Speed}=\frac{2400}{x+10}\ s$ = $\frac{Distance}{Speed}=\frac{2400}{x+10}\ s$

Speed of boat up stream = $\textrm{Speed of boat in still water -Speed of current}= (x-10)\ ms^{-1}$

Distance rowed up stream = $\frac{1}{6} \textrm{ of distance rowed downstream}=\frac{1}{6}\times 2400 = 400\ m$

Time spent rowing up stream = $\frac{Distance}{Speed}=\frac{400}{x-10}\ s$

We know that,

$\textrm{Time spent rowing down stream =Time spent rowing up stream}$

So,

$\frac{2400}{x+10}=\frac{400}{x-10}$

Cross multiplying

$2400(x-10)=400(x+10)$

Dividing both sides by $400$

$\frac{2400(x-10)}{400}=\frac{400(x+10)}{400}$

$6(x-10)=x+10$

$6x-60=x+10$

Adding 60 to both sides.

$6x-60+60=x+10+60$

$6x=x+70$

Subtracting both sides by $x$

$6x-x=x+70-x$

$5x=70$

Dividing both sides by 5.

$\frac{5x}{5}=\frac{70}{5}$

∴ $x=14$

Speed of boat in still water $=14\ ms^-1$

Time spent rowing down stream = $\frac{2400}{14+10}=\frac{2400}{24}=100\ s$

3 0

3 years ago