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Zielflug [23.3K]
3 years ago
13

please help if you know! lesson name: L 10.5: Using the Distributive Property here is the pic i don't understand

Mathematics
1 answer:
Andrei [34K]3 years ago
4 0

Answer:

Area of the shaded region = 1.72r²

Step-by-step explanation:

Radius of the circle = r

Length of the rectangle = 4r

Width of the rectangle = 2r

Area of the circle = πr²

Area of the rectangle = Length × Width

= 4r × 2r

= 8r²

Area of the shaded region = Area of the rectangle - 2 × Area of the circle

= 8r² - 2 × πr²

= 8r² - 2πr²

= r²(8 - 2π)

= r²(8 - 2 × 3.14)

= r²(8 - 6.28)

= 1.72r²

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andre [41]

Answer:

A line parallel has the same slope, so -3

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3 years ago
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Sophia uses 18 beads to make a necklace. Three sixths of the beads are purple. How many beads are purple?
joja [24]

Answer:

9 beads are purple

Step-by-step explanation:

we know that

To find out how many  beads are purple, multiply the total beads by the fraction of the beads that are purple

so

18(\frac{3}{6})=9\ beads

therefore

9 beads are purple

Another way to solve the problem is convert the fraction in percentage

we have

\frac{3}{6}=\frac{1}{2}=0.50*100=50\%

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If the total are 18 beads

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8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Cboxed%7B%20%5Cbegin%7Barray%7D%7B%7D%5Clarge%5Ctt%20The%20%20%5C%5C%20%20%5Ct
larisa86 [58]

Distance formula

\boxed{\sf \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}

Now

#1

\\ \tt\Rrightarrow AB=\sqrt{(3-3)^2+(-2-8)^2}=\sqrt{100}=10units

#2

\\ \tt\Rrightarrow OK=\sqrt{(5-7)^2+(-2+2)^2}=\sqrt{4}=2units

#3

\\ \tt\Rrightarrow LM=\sqrt{(-4-4)^2+(6+4)^2}=\sqrt{64+100}=\sqrt{164}\approx 13units

#4

\\ \tt\Rrightarrow PC=\sqrt{(5-2)^2+(1-3)^2}=\sqrt{9+4}=\sqrt{13}=3.2units

#5

\\ \tt\Rrightarrow QR=\sqrt{(-2+10)^2+(3-9)^2}=\sqrt{64+36}=\sqrt{100}=10units

8 0
3 years ago
Read 2 more answers
8. A triangle has sides with lengths of 6, 8, and 10 units, and a square has a
svet-max [94.6K]

Difference between the area of the triangle and square is 25

Step-by-step explanation:

  • Step 1: Find the area of the triangle given its 3 sides using the Heron's formula.

Area of the triangle = \sqrt{s (s-a)(s-b)(s-c)} where s = \frac{a + b + c}{2}

⇒ s = (6 + 8 + 10)/2 = 24/2 = 12

\sqrt{s(s-a)(s-b)(s-c)} = \sqrt{12(12-6)(12-8)(12-10)}

                                    = \sqrt{12(6)(4)(2)} = \sqrt{576} = 24 sq. units

  • Step 2: Find the area of the square with perimeter = 28 units.

Perimeter of the square = 4 × side = 28

⇒ Side of the square = 28/4 = 7 units

⇒ Area of the square = (side)² = 7² = 49 sq. units

  • Step 3: Find the difference between the area of the square and triangle.

Difference = 49 - 24 = 25

8 0
3 years ago
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