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eimsori [14]
2 years ago
9

Find the length of each arc. Round your answers to the nearest tenth. NO LINKS!! Part 1​

Mathematics
2 answers:
Hatshy [7]2 years ago
7 0
Answer:
5) 18.8 cm
7) 49.5 ft

Explanation:
The formula for arc length is S = θ * r

5) S = 18 cm * Pi/3 (60 degrees in radians)
S = 6 Pi cm
S ≈ 18.8 cm


7) S = 9 ft * 7 Pi / 4
S = 63 Pi ft / 4
S ≈ 49.5 ft
vesna_86 [32]2 years ago
3 0

Length of arc=r\theta

So

#1

\\ \rm\Rrightarrow Area=18(\pi/3)=6\pi cm

#2

\\ \rm\Rrightarrow Area=9(7\pi/4)=63\pi /4ft

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Select the equation of a straight line that is parallel to the line 4y = 3x + 5
insens350 [35]

Answer:

One equation can be y = 3/4X +2

Step-by-step explanation:

Any equation that has a slope of 3/4 will be parallel to the line 4Y = 3X + 5 because the slope is the same. This can also be shown visually using any graphing calculator.

8 0
3 years ago
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
2 years ago
If twice a number is subtracted from 11, the result is 4 more than the number. What is the number?
Flauer [41]

Let the number = x.

So 2 times x subtracted from 11 is written as 11-2x

The result is 4 more than the number is written as 4 +x

Now you have 11-2x = 4 + x

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Subtract 4 from each side:

7 = 3x

Divide both sides by 3:

x = 7/3

4 0
3 years ago
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guajiro [1.7K]

Answer:

He made Rs.500

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6 0
2 years ago
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ira [324]

Answer:

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Step-by-step explanation:

4 0
2 years ago
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