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algol [13]
3 years ago
7

Wilda can do a job in 4 hours that karla needs 5 hours to do. If wilda works 1 hour before karla joins her, how long will it tak

e the two of them to finish the job?
Mathematics
1 answer:
mezya [45]3 years ago
8 0
Wilda can do the job in 4 hours ... she does 1/4 (or 0.25) of it each hour.
Karla can do it in 5 hours ... she does 1/5 (or 0.2) of it each hour.

Wilda worked alone for 1 hour ... 0.25 of the job was done before her helper
arrived.  So only 0.75 of the job remained to be done together.

Working together, they accomplish (0.25 + 0.2) = 0.45 of the job in 1 hour.

How many times do they need to do  0.45  of the job in order to finish
the  0.75  of it that remains ?  That's the number of hours it will take them,
working together.

0.75 / 0.45  =  <em>1 and 2/3</em>

After Wilda worked alone for 1 hour and Karla came along to join her, it will
take them another  <em>1 hour and 40 minutes</em> to finish the job and go for a swim.
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Y_Kistochka [10]

Answer:

Area of the sector is 97.30 square feet.

Step-by-step explanation:

The area of the sector is given by

A=(\frac{\theta}{2})r^2

Plugging the known values in this formula to find the area of the sector

A=(\frac{2\pi/9}{2})(16.7)^2\\\\A=\frac{2\pi}{18}\cdot16.7^2

Use the value of π as 3.14

A=\frac{2\cdot3.14}{18}\cdot16.7^2

Simplifying, we get

A=97.3016

Rounded to the nearest hundredth, we get

A=97.30

8 0
3 years ago
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What term must go in the space to complete the statement
irakobra [83]

Answer:

5v+35 = 5(v+7)

Step-by-step explanation:

5(v+7) = 5v+35

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3 years ago
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The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.​
melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

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The nth term of an AP is:

\mathbf{T_n = a + (n - 1)d}

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

\mathbf{T_2 = a + d}

\mathbf{T_6 = a + 5d}

\mathbf{T_8 = a + 7d}

The <em>first, second and third terms </em>of the GP would be:

\mathbf{a_1 = a + d}

\mathbf{a_2 = a + 5d}

\mathbf{a_3 = a + 7d}

The common ratio (r) is calculated as:

\mathbf{r = \frac{a_2}{a_1}}

This gives

\mathbf{r = \frac{a + 5d}{a + d}}

The nth term of a GP is calculated using:

\mathbf{a_n = a_1r^{n-1}}

So, we have:

\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0
2 years ago
4^3 * 4^4 = <br> A) 4^-1<br> B) 4^1<br> C) 4^7<br> D) 4^12
lions [1.4K]
<h2>Hello!</h2>

The answer is:

The correct option is:

C) 4^{3}*4^{4}=4^{7}

<h2>Why?</h2>

To solve the problem, we need to remember the product of powers with the same base property, the property is defined by the following relation:

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If we are multiplying two or more powers with the same base, we must keep the base and add/subtract the exponents.

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4^{3}*4^{4}=4^{4+3}=4^{7}

Hence, we have that the correct option is:

C) 4^{3}*4^{4}=4^{7}

Have a nice day!

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