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GuDViN [60]
3 years ago
12

A rectangle's length is 7 less than 3 times it's width. If the perimeter of the rectangle is 170 inches, what is the width, leng

th and area of the rectangle?
Mathematics
1 answer:
rusak2 [61]3 years ago
5 0

Answer:

Length: 69

Width: 16

Area: 1104

Perimeter: 170

Explanation:

(69 + 69) + (16 + 16) = 138+32= 170

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To prepare for a triathlon, Amanda starts from position A and rides her bike along a straight road for 12 miles to reach positio
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Answer:


Step-by-step explanation:

Let's draw the given information first for better understanding . Check the image attached.

We can use cosine rule to find the angles .

for angle A ,

Cos A =\frac{b^2+c^2-a^2}{2bc}

Cos A =\frac{20^2+12^2-15^2}{2*20*12}

Cos A =\frac{319}{480}

m∠A = 48.35 degrees

Similarly for angle B

Cos B =\frac{a^2+c^2-b^2}{2bc}

Cos B =\frac{15^2+12^2-20^2}{2*15*12}

Cos B =\frac{-31}{360}

m∠B = 94.94 degrees

Now use A+B+C=180 degrees

48.35+94.94+C=180

C=180-48.35-94.94

m∠C = 36.71 degrees

3 0
3 years ago
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Which property of equality should be used with the equation c + 5 = 78 to solve?
rjkz [21]

Answer:

Subtraction property of equality

Step-by-step explanation:

c + 5 = 78

Subtract 5 from each side using the subtraction property of equality

c+5-5 = 78-5

x = 73

5 0
3 years ago
Frank has a batting average of .255. Write this decimal as a fraction in simplest form.
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6 0
3 years ago
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In the inequality 6a+4b>10, what could be the possible value of a if b=2?
Arlecino [84]

We are given the following inequality:

6a+4b>10

If we replace b = 2, we get:

\begin{gathered} 6a+4(2)>10 \\ 6a+8>10 \end{gathered}

Now we solve for "a" first by subtracting 8 on both sides:

\begin{gathered} 6a+8-8>10-8 \\ 6a>2 \end{gathered}

Now we divide both sides by 6

\frac{6a}{6}>\frac{2}{6}

Simplifying:

a>\frac{1}{3}

Therefore, for b = 2, the possible values of "a" are those that are greater than 1/3

3 0
1 year ago
What is the area of the semicircle?
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Step-by-step explanation:

Area (semi-circle)= \frac{r^2\pi }{2}

A = \frac{(11)^2\pi }{2}

A=\frac{121\pi }{2}

A=\frac{379.94}{2}

A=189.97

The area of the semi-circle is 189.97

6 0
2 years ago
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