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3 years ago

Help me solve this please

Mathematics

1 answer:

azamat3 years ago

6 0

√9 x √9 = 9
√6 x √6 = 6
√10 x √10 = 10

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You have a normal model. The population mean is 500 and standard deviation is 100. Which of the following options would be the c

mihalych1998 [28]

Answer:

a. N(500, 100)

Step-by-step explanation:

The normal probability distribution, with mean M and standard deviation S, can be represented in the following notation.

N(M,S).

In this problem, we have that:

Mean = 500

Standard deviation = 100

Which of the following options would be the correct way to represent the information?

a. N(500, 100)

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%28-81%29x%5E%7B2%7D%20%7D" id="TexFormula1" title="\sqrt{(-81)x^{2} }" alt="\sqrt{(

SSSSS [86.1K]

Answer:

We conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

Step-by-step explanation:

Given the radical expression

$\sqrt{\left(-81\right)x^2}$

simplifying the expression

$\sqrt{\left(-81\right)x^2}$

Remove parentheses: (-a) = -a

$\sqrt{\left(-81\right)x^2}=\sqrt{-81x^2}$

Apply radical rule: $\sqrt{-a}=\sqrt{-1}\sqrt{a},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=\sqrt{-1}\sqrt{81x^2}$

Apply imaginary number rule: $\sqrt{-1}=i$

$=i\sqrt{81x^2}$

Apply radical rule: $\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

$=\sqrt{81}i\sqrt{x^2}$

$=9i\sqrt{x^2}$

Apply radical rule: $\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$=9ix$

Therefore, we conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

7 0

2 years ago

HELPPPPPPPPPPPPPPPPPPPPPPP

ale4655 [162]

Answer:

The answer is 50

Step-by-step explanation:

1) multiply 6 by 7

2) multiply 4 by 2

3) add the products together

6 0

3 years ago

Read 2 more answers

$1,580 at 10% for 8 years

sp2606 [1]

The answer is 1738
Hope this helps you

8 0

2 years ago

How do you figure out the answer?

svp [43]

we can divide the composite shape into on quadrilateral and triangle as shown in the diagram. since the line that joins the two shape is parallel to the base AB, the angle DEC is 85°.The angle CEA is 180°- angle DEC = 180-85=95. Angle BCE is sum of angle CEA, ABC and EAB subtracted from360°= 360°-(95+95+85)=85°. Angle DCE is 120°- ECB=35°. So, angle CDE = 180°-(35°+85°)= 60°. For reference see the diagram.

7 0

3 years ago