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Nataly_w [17]
3 years ago
14

Plssss help i will give brainliest!!!!

Mathematics
2 answers:
Gnoma [55]3 years ago
5 0

Answer: the 4th one I think

Step-by-step explanation:

Mandarinka [93]3 years ago
5 0

Answer: the forth one :)

Step-by-step explanation:

You might be interested in
A scientist cools some water at a constant rate. the graph and table show how the temperature of the water changes with time.
irina1246 [14]

Answer:

C

Step-by-step explanation:

The easiest way to determine this is to realize that time is the independent variable (n) and temperature is the dependent variable (a).

From the table, we can plug in the two points (n) into n of each equation and see if that equals the temperature values (a).

<em>A little thinking would get us to plug the numbers in C first.</em>

<em>a(n)=46-(n-1)*4\\46-(5-1)*4=30</em>

<em>Works!!</em>

<em>Now, second number:</em>

<em>a(n)=46-(n-1)*4\\46-(6-1)*4=26</em>

<em>Works!!</em>

<em />

<em>Hence, C is the correct answer.</em>

6 0
3 years ago
Read 2 more answers
Simplify[-3]-[-5] by using a number line
Aleks [24]

Answer: 2

Step-by-step explanation: Add −3 and 5

3 0
3 years ago
Select each equation which is equivalent to 60% of 25.
Aleksandr [31]

Answer:

Step-by-step explanation:

The answer choices are not displaying properly. There are many ways to express the relation. For example:

X = 60% of 25

X = 0.60 × 25

X = 0.6 × 25

X = 60/100 × 25

X = 6/10 × 25

X = ⅗ × 25

6 0
3 years ago
Orthogonally diagonalize the​ matrix, giving an orthogonal matrix P and a diagonal matrix D. To save​ time, the eigenvalues are
alexgriva [62]

Answer:

P=\left(\begin{array}{ccc}-\frac{2}{3}&-\frac{2}{3}&\frac{1}{3}\\\frac{1}{\sqrt{5}}&0&\frac{2}{\sqrt{5}}\\-\frac{4}{3\sqrt{5}}&\frac{\sqrt{5}}{3}&\frac{2}{3\sqrt{5}}\end{array}\right)

Step-by-step explanation:

It is a result that a matrix A is orthogonally diagonalizable if and only if A is a symmetric matrix.  According with the data you provided the matrix should be

A=\left(\begin{array}{ccc}-9&-4&2\\ -4&-9&2\\2&2&-6\\\end{array}\right)

We know that its eigenvalues are \lambda_{1}=-14, \lambda_{2}=-5, where \lambda_{2}=-5 has multiplicity two.

So if we calculate the corresponding eigenspaces for each eigenvalue we have

E_{\lambda_{1}=-14}=\langle(-2,-2,1)\rangle,E_{\lambda_{2}=-5}=\langle(1,0,2),(-1,1,0)\rangle..

With this in mind we can form the matrices P, D that diagonalizes the matrix A so.

P=\left(\begin{array}{ccc}-2&-2&1\\1&0&2\\-1&1&0\\\end{array}\right)

and

D=\left(\begin{array}{ccc}-14&0&0\\0&-5&0\\0&0&-5\\\end{array}\right)

Observe that the rows of P are the eigenvectors corresponding to the eigen values.

Now you only need to normalize each row of P dividing by its norm, as a row vector.

The matrix you have to obtain is the matrix shown below

3 0
4 years ago
Helppppp please (: and thank you
Naily [24]

Answer:

5

Step-by-step explanation:

h(x) h(2)

h(x)=x^2-3. h(2)=2^2-3

g(h(2) g(h(2)=5

7 0
3 years ago
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