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gladu [14]
2 years ago
9

Some help with the circle problem would be much aprecated.

Mathematics
1 answer:
Oksana_A [137]2 years ago
8 0
Try this solution:
for the circle A: circumference=6π, area=9π
for the circle B: circumference=12π, area=36π

PS. formula for circumference is 'L=2πr', for area is 'S=πr²'.
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Multiply (3x-4)(6x+7
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(High points) please solve with explanation
AysviL [449]

Answer:

The area and the perimeter of the picture are:

  • <u>Area = 160 cm^2</u>
  • <u>Perimeter = 67.31 cm</u>

Step-by-step explanation:

To find the area of that figure, you can find the area how if it was a rectangle and next subtract the area of the triangle in the upper part. The area of a rectangle could be found by the next formula:

  • Area of a rectangle = base * height

As you can see in the picture, the base is 16 cm and the height is 12 cm, then we replace in the formula:

  • Area of a rectangle = 16 cm * 12 cm
  • Area of a rectangle = 192 cm^2

Now, we calculate the area of the triangle to subtract to the area we found and obtain the real area, the formula to obtain the area of a triangle is:

  • Area of a triangle = (base * height) / 2

The height of the triangle is 8 cm, and the base is 8 cm too, because you subtract to the base of the rectangle (16 cm) the measurements in the upper part (16 - 4 - 4 = 8), Now, we replace in the formula:

  • Area of a triangle = (8 cm * 8 cm) / 2
  • Area of a triangle = (64 cm^2) / 2
  • Area of a triangle = 32 cm^2

We subtract to the found area:

  • Area of the picture = 192 cm^2 - 32 cm^2
  • <u>Area of the picture = 160 cm^2</u>

To find the perimeter, you must add all the sides of the picture, but, as you can see, there is a side that doesn't have the measurent, this is the hypotenuse of the triangle used before, but how we know the other sides, we can use Pythagorean theorem:

  • a^{2}+b^{2}=c^{2}

Where:

  • a = Opposite leg (8 cm)
  • b = Adjacent leg (8 cm)

So, we replace in the theorem:

  • a^{2}+b^{2}=c^{2}
  • (8 cm)^{2}+(8cm)^{2}=c^{2} (and we clear c)
  • \sqrt{(8 cm)^{2}+(8cm)^{2}} =c
  • \sqrt{64 cm^{2}+64cm^{2}} =c
  • \sqrt{128cm^{2}} =c
  • c = 11.3137085 cm
  • c ≅ 11.31 cm

At last, we add all the sides of the picture begining by the base and going by the left side:

  • Perimeter of the picture = 16 cm + 12 cm + 4 cm + 11.31 cm + 8 cm + 4 cm + 12 cm
  • <u>Perimeter of the picture = 67.31 cm approximately</u>.
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