Answer:
15.71 ft
Step-by-step explanation:
Given that:
width of the circular track = 2.5ft
Suppose the radius of the inner circle is 57 ft since it is not given
Then the radius of the outer circle = (2.5 + 57) ft = 59.5 ft
The circumference of a circle = 2πr
For inner circle now, the circumference = 2 × π × 57 ft
For inner circle now, the circumference = 358.14 ft
For the outer circle, the circumference = 2 × π × 59.5 ft
For the outer circle, the circumference = 373.85 ft
The difference between the circumference of the outer wheel from the inner wheel shows how farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one turn
∴
= ( 373.85 - 358.14 ) ft
= 15.71 ft
Use formula a squared equals to c squared minus b squared
40^2-24^2 is 1024
Square root of 1024 is 32.0
Answer:
The answer is 0.9789 approximately equal to 0.9790
Step-by-step explanation:
See the attached files for the details, hope it is clearly understood.
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I’m pretty sure the answer is E. X is a linear function. Z is a cubed root function. W is a quadratic function and Y is exponential
The answer is 9(3+x)
My work is in the attached image
