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densk [106]
2 years ago
15

HELP. A triangle is dilated by a scale factor of 2 and the area of the original figure is x units.

Mathematics
1 answer:
7nadin3 [17]2 years ago
8 0

Answer:

4x.

Step-by-step explanation:

If the scale factor is 2 then the area factor is 2^2 = 4.

So the area of the new triangle is 4*x.

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Is 4/6 and 6/12 equivalent
larisa86 [58]
4/6
= (4/2) / (6/2)
= 2/3

6/12
= (6/6) / (12/6)
= 1/2

Because 2/3 ≠ 1/2, 4/6 and 6/12 are NOT equivalent.
3 0
2 years ago
Read 2 more answers
(Based on Q1 ~ Q3) According to the Bureau of the Census, 18.1% of the U.S. population lives in the Northeast, 21.9% inn the Mid
vekshin1

Answer:

We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.

Step-by-step explanation:

The null Hypothesis: Geographical distribution of hotline callers could be the same as the U.S. population distribution

Alternative hypothesis: Geographical distribution of hotline callers could not be the same as the U.S. population distribution

The populations considered are the Midwest, South, Northeast, and west.

The number of categories, k = 4

Number of recent calls = 200

Let the number of estimated parameters that must be estimated, m = 0

The degree of freedom is given by the formula:

df = k - 1-m

df = 4 -1 - 0 = 3

Let the significance level be, α = 5% = 0.05

For  α = 0.05, and df = 3,

from the chi square distribution table, the critical value = 7.815

<u>Observed and expected frequencies of calls for each of the region:</u>

<u>Northeast</u>

Observed frequency = 39

It contains 18.1% of the US Population

The probability = 0.181

Expected frequency of call = 0.181 * 200 = 36.2

<u>Midwest</u>

Observed frequency = 55

It contains 21.9% of the US Population

The probability = 0.219

Expected frequency of call = 0.219 * 200 =43.8

<u>South</u>

Observed frequency = 60

It contains 36.7% of the US Population

The probability = 0.367

Expected frequency of call = 0.367 * 200 = 73.4

<u>West</u>

Observed frequency = 46

It contains 23.3% of the US Population

The probability = 0.233

Expected frequency of call = 0.233 * 200 = 46

x^{2} = \sum \frac{(O_{i} - E_{i})  ^{2} }{E_{i} } ,   i = 1, 2,.........k

Where O_{i} = observed frequency

E_{i} = Expected frequency

Calculate the test statistic value, x²

x^{2} = \frac{(39 - 36.2)^{2} }{36.2} + \frac{(55 - 43.8)^{2} }{43.8} + \frac{(60 - 73.4)^{2} }{73.4} + \frac{(46 - 46.6)^{2} }{46.6}

x^{2} = 5.535

Since the test statistic value, x²= 5.535 is less than the critical value = 7.815, the null hypothesis will not be rejected, i.e. it will be accepted. We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.  

7 0
2 years ago
PLEASE HELP ME WITH THIS QUESTION!!!
mojhsa [17]
The answer is no solution
3 0
3 years ago
Find the value of x.<br> A. 22.5<br> B.40<br> C.45<br> D.95
Troyanec [42]

Answer:

x = 22.5

Step-by-step explanation:

The tangent- secant angle x is half the difference of the measures of the intercepted arcs, that is

\frac{1}{2} (4x + 5 - 50 ) = x ( multiply both sides by 2 )

4x - 45 = 2x ( subtract 2x from both sides )

2x - 45 = 0 ( add 45 to both sides )

2x = 45 ( divide both sides by 2 )

x = 22.5

4 0
2 years ago
What is the constant of proportionality in the equation y = 5/3x? ​
Alja [10]
3/5 explanation because I’m big brain boii
6 0
2 years ago
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