41.8 rounded to the nearest tenth
Differentiating an integral removes the integral.
f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.
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Answer:
27.4 km
Step-by-step explanation:
vertical line- y
17 km/y= tan 54
y= 17/tan 54= 25.2 km
25.2/x= cos 23
x= 25.2/cos 23= 27.4 km
Hope this helps
3,-13
-1,3
0,-1
3,-13
