Find a formula for the nth term in this

Mathematics

1 answer:

stepan [7]1 year ago

3 0

The formula of nth term is = 10 - 3n

What is AP?

A series of numbers called an arithmetic progression or arithmetic sequence (AP) has a constant difference between the terms. Take the numbers 5, 7, 9, 11, 13, and 15 as an example. . . is a sequence of numbers having a common difference of two.
The n-th term of the sequence is given by:, if the beginning term of an arithmetic progression is and the common difference between succeeding members is, then
If the AP contains m phrases, then denotes the final term, which is given by:
The term "finite arithmetic progression" or "arithmetic progression" refers to a finite segment of an arithmetic progression. An arithmetic series is the total of a finite arithmetic progression.

Acc to our question-

For the nth term in an algebraic series
U(n) = a + (n - 1)d
the number of terms is n.
The first term is a.
d is the typical difference
From the preceding sequence
a = 7
d = 4 - 7 = - 3
The nth term's formula is
U(n) = 7 + (n - 1)-3
= 7 - 3n + 3
The ultimate solution is
= 10 - 3n

Hence,The formula of nth term is = 10 - 3n

learn more about AP click here:

brainly.com/question/6561461

#SPJ13

You might be interested in

Please someone help me out. I beggggg

bezimeni [28]

Answer:

1. 144 2. 16 3. 1 4. 3x-6

Step-by-step explanation:

So think of this as a function in a function. So you work from the inside to the outside. So for problem 1, we start with f(4)) [you read it "f of 4"] so what is the solution when x = 4, since f(x) means the function of x so f(4) means 'the function of 4' inside f(x).

Since f(x) = 3x then f(4) = 3(4) [notice how you substitute the 4 everywhere you see a letter x]

so f(4) = 12, now you work the next part h(f(4)) since f(4)=12 then h(12)

So take the h(x) function which is h(x) = $x^{2}$ then h(12) = $12^{2}$ so h(12) = 144