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2 years ago

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Give an example of a function that is neither even nor odd and explain algebraically why it is neither even nor odd

1 answer:

bogdanovich [222]2 years ago

8 0

An odd function is the negative function that results from the replacement of x with -x in the expression. An even function stays the same even after the substitution. An example of a neither even or odd function is f(x) = 2x3 – 3x2 – 4x + 4. when we substitute -x to x, the resulting is f(x) =–2x3<span> –3</span>x2<span> + 4</span>x<span> + 4 which is not equal to the original or the negative counterpart.</span>

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The following picture is a square pyramid where DE=8 cm and m∠ADE=60°.

Goryan [66]

<u>Given</u>:

The length of DE is 8 cm and the measure of ∠ADE is 60°.

We need to determine the surface area of the pyramid.

<u>Length of AD:</u>

The length of AD is given by

$cos 60^{\circ}=\frac{FD}{8}$

$4=FD$

Length of AD = 8 cm

<u>Slant height:</u>

The slant height EF can be determined using the trigonometric ratio.

Thus, we have;

$sin \ 60^{\circ}=\frac{EF}{8}$

$sin \ 60^{\circ} \times 8=EF$

$\frac{\sqrt{3}}{2} \times 8=EF$

$4\sqrt{3}=EF$

Thus, the slant height EF is 4√3

<u>Surface area of the square pyramid:</u>

The surface area of the square pyramid can be determined using the formula,

$SA=Area \ of \ square + \frac{1}{2} (Perimeter \ of \ base ) (slant \ height)$

Substituting the values, we have;

$SA=8^2+\frac{1}{2}(8+8+8+8)(4 \sqrt{3})$

$SA=64+\frac{1}{2}(32)(4 \sqrt{3})$

$SA=64+(16)(4 \sqrt{3})$

$SA=64+64 \sqrt{3}$

The exact form of the area of the square pyramid is $64+64 \sqrt{3}$

Substituting √3 = 1.732 in the above expression, we have;

$SA = 64 + 110.848$

$SA = 174.848$

Rounding off to one decimal place, we get;

$SA = 174.8$

Thus, the area of the square pyramid is 174.8 cm²

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2 years ago

Read 2 more answers

Whats next 2 numbers in this pattern 4,20,100,500.....

Korolek [52]

The next two patterns are 2,500 12,500

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Which expression represents: twice a number increased by 39

Cerrena [4.2K]

Answer:

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Step-by-step explanation:

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3 years ago

Find the roots of the equation x^2+2x+5=0

stiv31 [10]

Answer:

x = - 1 ± 2i

Step-by-step explanation:

we can use the discriminant b² - 4ac to determine the nature of the roots

• If b² - 4ac > , roots are real and distinct

• If b² - 4ac = 0, roots are real and equal

• If b² - ac < 0, roots are not real

for x² + 2x + 5 = 0

with a = 1, b = 2 and c = 5, then

b² - 4ac = 2² - (4 × 1 × 5 ) = 4 - 20 = - 16

since b² - 4ac < 0 there are 2 complex roots

using the quadratic formula to calculate the roots

x = ( - 2 ± $\sqrt{-16}$ ) / 2

= (- 2 ± 4i ) / 2 = - 1 ± 2i

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3 years ago