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siniylev [52]
2 years ago
6

Give an example of a function that is neither even nor odd and explain algebraically why it is neither even nor odd

Mathematics
1 answer:
bogdanovich [222]2 years ago
8 0
An odd function is the negative function that results from the replacement of x with -x in the expression. An even function stays the same even after the substitution. An example of a neither even or odd function is f(x) = 2x3 – 3x2 – 4x + 4. when we substitute -x to x, the resulting is f(x) =–2x3<span> –3</span>x2<span> + 4</span>x<span> + 4 which is not equal to the original or the negative counterpart.</span>
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PLEASE HELP! WILL GIVE BRAINLIEST!
ANTONII [103]

Answer:

(18+21+17+x)÷4=20

x=24 students

Step-by-step explanation:

(18+21+17+x)÷4=20

(56+x)÷4=20

56+x=20*4

56+x=80

x=80-56

x=24

8 0
3 years ago
Which number is equal to 10 Superscript negative 3? â€"1,000 â€"30 0. 001 0. 3.
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Answer:

0.001

Step-by-step explanation:

10^{-3}=\dfrac{1}{10^{3}}=\frac{1}{1000}=0.001

3 0
2 years ago
Jack is considering a list of features and fees for Current Bank: Jack plans on using network ATMs about 4 times per month. What
bekas [8.4K]
I think it’s b but if you don’t agree with me that’s fine
5 0
3 years ago
Which equation has a constant of proportionality equal to 2?
Blababa [14]

Answer:

A) y = 10/5x

10 divided by 5 = 2

Step-by-step explanation:

I hope it helps ❤❤

3 0
2 years ago
Read 2 more answers
Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believe
Stolb23 [73]

Answer:

Step-by-step explanation:

The model N (t), the number of planets found up to time t, as a Poisson process. So, the N (t) has distribution of Poison distribution with parameter (\lambda t)

a)

The mean for a month is, \lambda = \frac{1}{3} per month

E[N(t)]= \lambda t\\\\=\frac{1}{3}(24)\\\\=8

(Here. t = 24)

For Poisson process mean and variance are same,

Var[N (t)]= Var[N(24)]\\= E [N (24)]\\=8

 

(Poisson distribution mean and variance equal)

 

The standard deviation of the number of planets is,

\sigma( 24 )] =\sqrt{Var[ N(24)]}=\sqrt{8}= 2.828

b)

For the Poisson process the intervals between events(finding a new planet) have  independent  exponential  distribution with parameter \lambda. The  sum  of K of these  independent exponential has distribution Gamma (K, \lambda).

From the given information, k = 6 and \lambda =\frac{1}{3}

Calculate the expected value.

E(x)=\frac{\alpha}{\beta}\\\\=\frac{K}{\lambda}\\\\=\frac{6}{\frac{1}{3}}\\\\=18

(Here, \alpha =k and \beta=\lambda)                                                                      

C)

Calculate the probability that she will become eligible for the prize within one year.

Here, 1 year is equal to 12 months.

P(X ≤ 12) = (1/Г  (k)λ^k)(x)^(k-1).(e)^(-x/λ)

=\frac{1}{Г  (6)(\frac{1}{3})^6}(12)^{6-1}e^{-36}\\\\=0.2148696\\=0.2419\\=21.49%

Hence, the required probability is 0.2149 or 21.49%

5 0
2 years ago
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