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Dmitrij [34]
2 years ago
15

3/5 of the balls in a box are red . The rest are green and red .The ratio of the number of balls to the number of yellow balls i

s 5:3 .If there are 10 less balls yellow balls than green balls , how many balls are red?​
Mathematics
2 answers:
just olya [345]2 years ago
6 0

Answer:

Hello this question is impossible ask your teacher or find if you didnt make any mistake copying this HW.

Step-by-step explanation:

You have 3x/5 red balls but next sentence is talking about that Yellow balls have to be in ratio 5:3 but it is impossible because Red balls + Yellow balls would make 6x/5 of balls which is not possible  

jolli1 [7]2 years ago
3 0

Answer:

not possible

Step-by-step explanation:

it ant be possibe as the answer would come out as 6x/5 which is incorrect.

sorry

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lys-0071 [83]
Use the compound interest formula

A = P (1 + r/n)^(nt).

Here A = unknown; B = initial amount = $300;
r = rate = 0.0218; n = 2 (2 compounding periods per year); and t = 1/2 (year).

Then A = $300 (1+0.0218/2)^(2*[1/2])
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Studentka2010 [4]

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Step-by-step explanation:

4 0
2 years ago
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What is the surface area of a cube if it has one side that is 40 cm
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5 0
2 years ago
WILL MARK BRAINLIEST! PLEASE HELP!<br> Write 206 in base 7
Anna71 [15]

Answer:

413_7

Step-by-step explanation:

Convert the following to base 7:

206_10

Hint: | Starting with zero, raise 7 to increasingly larger integer powers until the result exceeds 206.

Determine the powers of 7 that will be used as the places of the digits in the base-7 representation of 206:

Power | \!\(\*SuperscriptBox[\(Base\), \(Power\)]\) | Place value

3 | 7^3 | 343

2 | 7^2 | 49

1 | 7^1 | 7

0 | 7^0 | 1

Hint: | The powers of 7 (in ascending order) are associated with the places from right to left.

Label each place of the base-7 representation of 206 with the appropriate power of 7:

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | __ | )_(_7)

Hint: | Divide 206 by 7 and find the remainder. The remainder is the first digit from the right.

Determine the value of the first digit from the right of 206 in base 7:

206/7=29 with remainder 3

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 29, by 7 and find the remainder. The remainder is the next digit.

Determine the value of the next digit from the right of 206 in base 7:

29/7=4 with remainder 1

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | 1 | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 4, by 7 and find the remainder. The remainder is the last digit.

Determine the value of the last remaining digit of 206 in base 7:

4/7=0 with remainder 4

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | 4 | 1 | 3 | )_(_7)

Hint: | Express 206_10 in base 7.

The number 206_10 is equivalent to 413_7 in base 7.

Answer: 206_10 =413_7

5 0
2 years ago
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