From the given figure, it can be seen that 13x = 15x - 8 because they are vertical angles and thus are equal.
13x = 15x - 8
15x - 13x = 8
2x = 8
x = 8/2 = 4
Thus, 15x - 8 = 15(4) - 8 = 60 - 8 = 52.
RT is a diameter, which means that mRT = 180
mRV + mVU + 52 = 180
mRV + mVU = 180 - 52 = 128
Now, given that mRV = mVU,
Thus, 2mVU = 128
Therefore, mVU = 128 / 2 = 64°
Slope of AB = 1/3 and slope of BC = -3 so these 2 lines are perpendicular
The same is true for all the other adjjacent pairs of lines.
Oppoitse lines are also paralllel ( slope of AB = 1/3 and slope of DC = 1/3) and other pair are both of slope -3.
So Its C
Answer:
J 8.5 >=2.5p
Step-by-step explanation:
To do this plug in 3.4 for each version of p. The only one that would be true would be J.
9514 1404 393
Answer:
A. no
B. no
C. obtuse
Step-by-step explanation:
For side lengths to form a triangle, the sum of the shorter two must exceed the longest.
A. 5 + 8 = 13 . . . . a line segment, not a triangle
B. 7 + 12 < 26 . . . . no closure, not a triangle
C. 11 + 15 > 20 . . . . a triangle. A picture shows it to be obtuse
You can also compare 11² +15² vs 20² ⇒ 346 vs 400. The long side is too long for a right triangle, so the triangle must be obtuse. (The Pythagorean theorem tells you a right triangle with those legs would have a long side of √346 = 18.6.)
Answer:
The standard parabola
y² = -18 x +27
Length of Latus rectum = 4 a = 18
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given focus : (-3 ,0) ,directrix : x=6
Let P(x₁ , y₁) be the point on parabola
PM perpendicular to the the directrix L
SP² = PM²
(x₁ +3)²+(y₁-0)² = 
x₁²+6 x₁ +9 + y₁² = x₁²-12 x₁ +36
y₁² = -18 x₁ +36 -9
y₁² = -18 x₁ +27
The standard parabola
y² = -18 x +27
Length of Latus rectum = 4 a = 4 (18/4) = 18