Answer with Step-by-step explanation:
We are given that a function f(x) is continuous on (
).
1.f'(-1)=0 and f''(-1)=-7
We have to find information about f.
When f'(-1)=0 and f''(-1)=-7 < 0
Then, function is maximum at x=-1.
Therefore, at x=-1, f has local maximum.
Answer:a)at x=-1 ,f has local maximum.
2.) if f'(4)=0 and f''(4)=0
We know that when f''(x)=0 then test fails then the function has not maximum or minimum.
Therefore, at x=4 , f has not a maximum or minimum.
Answer:c) at x=4, f has not a maximum or minimum.
1/27
1/27
125
Step-by-step explanation:
Given that,
a - b = 3
9^(1/2b) /3^a = 3^(2/2b) /3^a
= 3^b/3^a
= 3^(b-a)
= 3^(-3)
= 27^(-1)
= 1/27
27^(1/3b) /9^(1/2a) = 3^(3/3b) /3^(2/2a)
= 3^b/3^a
= 3^(b-a)
= 3^(-3)
= 27^(-1)
= 1/27
125^(1/3a) /25^(1/2b) = 5^(3/3a) /5^(2/2b)
= 5^a/5^b
= 5^(a- b)
= 5^3
= 125
The answer is 10.95445 and it is irrational because it is not a full square
They're all used for differentiating types of measurement in mathematics and science.
Answer:
The broker's commission was rupees 8,250
Step-by-step explanation:
Selling price of property = rupees 450,000
The sale price is higher than rupees 300,000
Commission for rupees 300,000 = 2% × rupees 300,000 = rupees 6,000
Remaining amount = rupees 450,000 - rupees 300,000 = rupees 150,000
Commission for the remaining amount = 1.5% × rupees 150,000 = 0.015 × rupees 150,000 = rupees 2,250
Total commission = rupees 6,000 + rupees 2,250 = rupees 8,250
