Answer:
(1) .20 (2) .40 (3) .12 (4) Less than
Step-by-step explanation:
You have to look at the table. There are 5 columns with 10 rows. 5x10=50
Then simply count the boxes that have the correct number of currency for instance, if they are asking for EXACTLY 1 dime then you rule out the ones that have 2 or 3 dimes and only the count the ones that have a single dime. So you count PDN but you would not count PDD. There are 20 boxes that have a single dime in them. 20 out of the 50 boxes. 20/50=.40 (answer 2)
The estimated probability that exactly two of the three coins Avery randomly picked are nickels is .
20
The estimated probability that exactly one of the three coins Avery randomly picked is a dime is .
40
The estimated probability that all three coins Avery randomly picked are pennies is .
12
The answer to #1 is .20 or 20% and the answer to #2 is .40 or 40%. 20% is less than 40% so...
The estimated probability that exactly two of the three coins Avery randomly picked are nickels is LESS THAN the estimated probability that exactly one of the three coins Avery randomly picked is a dime.
Answer:
Step-by-step explanation:
You take the starting year of 1990 and subtract it from 1999 to get the year span of 9,
You then take the amount per year the population goes up by which is 300, so 300 multiplied by 9 is 2,700
You add 2,700 to 21,152 to get B-23,852
Answer:
Sam's thinking was incorrect.
On number first we have to move 10 units from 0 in positive direction after that negative sign means move in left direction.
But we have 2 negative signs so we need to move 6 units more on positive or right direct as shown below.
Step-by-step explanation:
