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Ahat [919]
3 years ago
12

A sphere has a surface area of 36 pi ft square. find the volume of the sphere

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
5 0
SA=4pir^2
V=(4/3)hpir^2


given
SA=36pi
36pi=4pir^2
divide by 4pi
9=r^2
sqrt both sides
3=r


v=(4/3)pir^3
v=(4/3)pi3^3
V=4pi9
v=36pi

36pi cubic feet
podryga [215]3 years ago
5 0
<h2>Answer:</h2>

The volume of the sphere is:

                  36\pi\ \text{cubic\ feet}

<h2>Step-by-step explanation:</h2>

Let us consider a sphere with radius r.

We know that the surface area(SA) of the sphere is given by:

       SA=4\pi r^2

and the volume(V) of the sphere is given by:

V=\dfrac{4}{3}\pi r^3

Here we have:

Surface area of sphere=  36 pi ft square.

i.e.

4\pi r^2=36\pi\\\\i.e.\\\\r^2=\dfrac{36\pi}{4\pi}\\\\i.e.\\\\r^2=\dfrac{36}{4}\\\\i.e.\\\\r=\sqrt{\dfrac{36}{4}}\\\\i.e.\\\\r=\sqrt{9}\\\\i.e.\\\\r=3\ units

and the Volume of sphere will be:

V=\dfrac{4}{3}\pi r^3\\\\i.e.\\\\V=\dfrac{4}{3}\pi (3)^3\\\\i.e.\\\\V=36\pi\ \text{cubic\ feet}

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Pythagorean theorem 19^2 + 21^2=x^2
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Answer:

x = 28.32 units.

Step-by-step explanation:

Given:

Longer leg = 21

Shorter leg = 19

Hypotenuse = x

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Hypotenuse = x = ?

Solution:

Pythagoras Theorem States that

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

Substituting of the given value above equation we get

x^{2} =21^{2}+ 19^{2}\\ \\x^{2}=441 + 361\\\\x^{2}=802\\ \therefore x=\pm\sqrt{802} \\\textrm{as x cannot be negative}\\\therefore x=\sqrt{802}\\\\\therefore x=28.319\ units\\\therefore x=28.32\ units

7 0
3 years ago
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Answer:

False

Step-by-step explanation:

When a figure is dilated by a scale factor of 4, the new figure produced will be 4 times the size of the original figure. This means that, the size would change while the shape remains the same as the original figure.

Congruent figures must have the same shape and size.

Therefore, the figure produced when a dilation of scale factor of 4 is done is not a congruent figure. Rather, it is a similar figure.

So, get statement is FALSE.

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Simplify the square root.<br> 6-63
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Three of the four vertices of a rectangle are located at (4, 2), (7, 2) and (4, 8). a. What are the coordinates of the missing v
34kurt

Answer:

a) The coordinates of the missing vertex = (7, 8)

b) Area = 18 square units

   Perimeter = 18 units

Step-by-step explanation:

a) We know three of the four vertices:

A: (4, 2)           C ______ D(?)

B: (7, 2)               |             |

C: (4, 8)           A |______| B  

To find the coordinates of the missing vertex we need to calculate the distance in the x-direction from point A to point B:

B_{x} - A_{x} = 7 - 4 = 3                    

Hence, the distance of point D from point C in the x-direction is:

D_{x} = C_{x} + 3 = 4 + 3 = 7

Now, to find the coordinate in "y" we need to calculate the distance in the y-direction between point C and point A:

C_{y} - A_{y} = 8 - 2 = 6  

Then, the distance of point D from point B in the y-direction is:

D_{y} = B_{y} + 6 = 2 + 6 = 8

Therefore, the coordinates of the missing vertex (point D) are:

D = (D_{x}, D_{y}) = (7, 8)    

b) The area of the rectangle is:

a = (B_{x} - A_{x})*(C_{y} - A_{y}) = 3*6 = 18 units^{2}

The perimeter is given by:

p = 2*(3 + 6) = 18 units

I hope it helps you!          

8 0
3 years ago
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