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Serhud [2]
3 years ago
6

Write the value of underlined digit 5165874

Mathematics
1 answer:
nlexa [21]3 years ago
3 0
Which is the underlined digit
 which number is underlined
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Rewrite the rational exponent as a radical by extending the properties of integer exponents.
Snezhnost [94]
\cfrac{2^{ \frac{3}{4} }}{2^{ \frac{1}{2} }}=2^{ \frac{3}{4} - \frac{1}{2} } =2^{ \frac{3}{4}-  \frac{2}{4} }=2^{ \frac{1}{4} }= \sqrt[4]{2}
7 0
3 years ago
Find the sum of the series 9+3+1+........+1/27​
Elina [12.6K]

Answer:

364/27

Step-by-step explanation:

9, 3, 1, ... is a geometric sequence with common ratio r = 1/3.

 

The nth term is a1rn-1.

 

If a1rn-1 = 1/27, then 9(1/3)n-1 = 1/27

 

                                32(3-1)n-1 = 3-3

 

                                3231-n = 3-3

 

                                    33-n = 3-3

 

                                      3-n = -3

 

                                         n = 6

 

The sum, Sn, of the first n terms of a geometric sequence is given by Sn = a1(1 - rn) / (1 - r).

 

So, 9 + 3 + 1 + ... + 1/27 = S6 = 9(1 - (1/3)6) / (1 - 1/3)

 

                                              = 9(1 - 1/729) / (2/3)

 

                                              = (27/2)(728/729) = 364/27

4 0
3 years ago
What is the value of c in the equation below? StartFraction 5 Superscript 5 Baseline Over 5 squared EndFraction = a Superscript
maw [93]

Answer:

125

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Instructions: Find the common difference of the arithmetic sequence.<br> 7.05, 7.15, 7.25,7.35, 7.45
zzz [600]
I believe that the common difference would be.10
7 0
3 years ago
Read 2 more answers
Running out of time! Please help and show work! Thank you! Will mark brainliest!
VikaD [51]
<h3>​(-3j²k³)²(2j²k)³</h3>

(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.​</em>

​= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>

​= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>

= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.​</em>

= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹​

​Answer = 72j¹⁰k⁹

​Hope this helps!​​​​

​​\textit{\textbf{Spymore}}​​​​​​

5 0
3 years ago
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