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Maksim231197 [3]
3 years ago
6

Solve 3(xx)+x-5 using the first principle

Mathematics
2 answers:
brilliants [131]3 years ago
8 0

Answer:

3x^2+x-5

Step-by-step explanation:

3\left(xx\right)+x-5

Remove parenthesis

3xx+x-5

Multiply x \times x=x^2

3x^2+x-5

Bingel [31]3 years ago
4 0

Answer:

3x²+x-5

Step-by-step explanation:

= 3(xx)+x-5

According to the rule, when bases are same powers are to be added.

= 3(x¹x¹)+x-5

= 3(x¹⁺¹)+x-5

= 3x²+x-5

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Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)
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\huge\boxed{y-5&=-\frac{1}{3}(x+9)}

First, we'll find the slope of the new line. The first line has a slope of 3. Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by -1) to get -\frac{1}{3} for the new slope.

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Answer: The top of the Crane is 31 feet above the ground.

Step-by-step explanation:

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