P minus 1 equals 5 p plus 3 p minus 8
2 answers:
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<h2>Answer:</h2>
<h2>Explanations:</h2>
![\begin{gathered} D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ D=\sqrt[]{(20-4)^2+(-9-3)^2} \\ D=\sqrt[]{16^2+(-12)^2} \\ D=\sqrt[]{256+144} \\ D=\sqrt[]{400} \\ D=20\text{units} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20D%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B%2820-4%29%5E2%2B%28-9-3%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B16%5E2%2B%28-12%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B256%2B144%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B400%7D%20%5C%5C%20D%3D20%5Ctext%7Bunits%7D%20%5Cend%7Bgathered%7D)
The standard equation of a circle is expressed according to the equation
where;
(a, b) is the coordinate of the centre of the circle
r is the radius of the circle;
Get the diameter of the circle;
For the radius of the circle;
Get the centre of the circle. Note that the centre will be the midpoint of the given endpoints as shown;
Substitute the centre (12, 3) and the radius 10 units into the equation of the circle above to have:
This gives the equation of the circle whose diameter is the segment with endpoints (4,3) and (20,-9).