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2 years ago

Simplify the expression x^5*x^7

Mathematics

2 answers:

goldenfox [79]2 years ago

7 0

Answer:

x^12

Step-by-step explanation:

professor190 [17]2 years ago

3 0

Answer:

The following expression would be simplified to x^12. According to the fundamental power laws associated with multiplying powers with the same integral numbers.

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Nicole wants to paint this figure on her wall in her bedroom. If paint cost $4.59 per square unit, how many square feet of paint

Crank

Answer: C.8 sq ft hope this helps:)

4 0

3 years ago

A rental hall has 60 tables.

luda_lava [24]

Answer:for the second question/First question that is unsolved it's

350

for the second unsolved question its200

for the third unsolved one its 550

Step-by-step explanation:

The first one is wrong 55%=35

45%=25

35x10=350

25x8=200

add it =550

7 0

3 years ago

400 A whole number a integer a real number or rational number

bearhunter [10]

Answer:

All of the above

Step-by-step explanation:

A whole number and integers are numbers that don't have decimals.

A rational number is a number that can be written as a fraction

A real number is any number that is not complex, which means that it has an imaginary solution or imaginary number part of it.

7 0

3 years ago

Find all the zeros of the equation x^4-6x^2-7x-6=0

rusak2 [61]

Answer:

The zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

$a_0=6,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}$

$-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2$

$=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\$

$=x^3-2x^2-2x-3$

Again factor using the rational root test, we get

$=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)$

Using the zero product rule, we have

$x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Therefore, the zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

4 0

3 years ago

Read 2 more answers

Which expression is a difference of a number and a product?

zaharov [31]

Option A i believe but i dont know for sure

5 0

2 years ago