All categories

3 years ago

Simplify the expression x^5*x^7

Mathematics

2 answers:

goldenfox [79]3 years ago

7 0

Answer:

x^12

Step-by-step explanation:

professor190 [17]3 years ago

3 0

Answer:

The following expression would be simplified to x^12. According to the fundamental power laws associated with multiplying powers with the same integral numbers.

You might be interested in

If Sarah has 30 bills in her wallet worth $240, all fives and tens, how many of each bill does she have? help

Ivenika [448]

Answer:

12 fives and 18 tens

Step-by-step explanation:

solving this we need 2 different equations

one for he total bills and one for the total money

x+y=30

that is total bills

5x+10y=240

combining both equations we can use elimination method and get

12 five dollar bills and 18 ten dollar bills

5 0

3 years ago

When the center of Earth is 3.8 × 105 kilometers from the center of the moon, the force of gravity between Earth and the moon is

kow [346]

I think the answer to you question is 35 i might be wrong tho but it may work.

7 0

3 years ago

What can you tell about the mean of each distribution? Help plz for real!!

worty [1.4K]

Step-by-step explanation:

Mean=sum of observations/no. of observations

7 0

3 years ago

The polynomial x^2+3x-1 is a factor of x^4+3x^3-2x^2-3x+1 true or false?

pashok25 [27]

Answer:

Yes, it is true that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ .

Step-by-step explanation:

Let us try to factorize $x^4+3x^3-2x^2-3x+1$

$x^4+3x^3-2x^2-3x+1\\\Rightarrow x^4-2x^2+1-3x+3x^3$

Let us try to make a whole square of the given terms:

$\Rightarrow (x^2)^2-2\times x^2 \times 1+1^2+3x^3-3x\\\Rightarrow (x^2-1)^2+3x^3-3x\\$

--------------

Formula used above:

$a^{2} -2 \times a \times b +b^{2} = (a-b)^2$

In the above equation, we had $a = x, b = 1$ .

--------------

Further solving the above equation, taking $3x$ common out of $3x^3-3x$

$\Rightarrow (x^2-1)^2+3x(x^2-1)\\$

Taking $(x^{2} -1)$ common out of the above term:

$\Rightarrow (x^2-1)((x^2-1)+3x)\\\Rightarrow (x^2-1)(x^2+3x-1)$

So, the two factors are $(x^2-1)\ and\ (x^2+3x-1)$ .

$\therefore$ The statement that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ is <em>True.</em>

7 0

3 years ago

the sum of three numbers is 55. the second number is twice the first and the third number is five less than the second. What are

ArbitrLikvidat [17]

Let the first number be = x

Then the second number = 2x

The third number = 2x - 5

Their sum = 55

This can be written in an equation as =

x + 2x + 2x - 5 = 55

= x + 2x + 2x = 55 + 5 ( transposing -5 from LHS to RHS changes -5 to +5 )

= x + 2x + 2x = 60

= 5x = 60

= x = 60 ÷ 5 ( transposing ×5 from LHS to RHS changes ×5 to ÷5 )

= x = 12

The first number = x = 12

The second number = 2x = 2 × 20 = 24

The third number = 2x - 5 = 24 - 5 = 19

Therefore , the three numbers are 12 , 24 and 19 .

5 0

3 years ago