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Anton [14]
3 years ago
7

Which value of n makes the following equation true?

Mathematics
1 answer:
grin007 [14]3 years ago
6 0

Answer: d. 512

Step-by-step explanation:

You need to remember that:

(\sqrt[3]{x})^3=x

Then, given the equation:

\sqrt[3]{n}=8

You can find the value of "n" that make the equation true, by solving for "n".

So, to solve for "n", you need to raise both side of the equation to power 3. Therefore, you get:

 \sqrt[3]{n}=8

 (\sqrt[3]{n})^3=(8)^3

 n=512

Then, the value of "n" that makes the equation \sqrt[3]{n}=8 true is: 512 (You can observe that this matches with the option d).

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One side if the labtop is 9.5 inches and the other side is 14 inches. Using the Pythagorean Theron, what is the length of the di
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The given matrix equation is,

1.5\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y\left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right].

Multiplying the matrices with the scalars, the given equation becomes,

\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]  \\

Adding the matrices,

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Matrix equality gives,

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We can see that the equations are not consistent.

There is no solution.

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Step-by-step explanation:

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