Answer:
4000×.06×2 which is 480
Step-by-step explanation:
You must times the money by the ir and then the year. Or money times the year then ir, it wouldn't really matter as long you times the three of them together
Answer:
6.5 cm
Step-by-step explanation:
Here, <em>the tangent line squared is equal to the secant line times the secant line outside the circle</em>.
That is <em>20.2² = 14.7 * (14.7 + 2x)</em> --> it is 2x because the secant goes through <em>the whole circle</em>.
Simplify: <em>408.04 = 216.09 + 29.4x</em>
Subtract: <em>191.95 = 29.4x</em>
Divide: <em>x = 6.528911565</em> ≈ 6.5 cm
Answer:
15
Step-by-step explanation:
H - 7
When H = 22, replace H with 22 in the equation.
22 - 7 = 15
Answer:
Translation
Step-by-step explanation:
The object is only moved, which is what happens when a translation occurs
A = event the person got the class they wanted
B = event the person is on the honor roll
P(A) = (number who got the class they wanted)/(number total)
P(A) = 379/500
P(A) = 0.758
There's a 75.8% chance someone will get the class they want
Let's see if being on the honor roll changes the probability we just found
So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).
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A and B = someone got the class they want and they're on the honor roll
P(A and B) = 64/500
P(A and B) = 0.128
P(B) = 144/500
P(B) = 0.288
P(A | B) = P(A and B)/P(B)
P(A | B) = 0.128/0.288
P(A | B) = 0.44 approximately
This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.
Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.
Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.