To solve this problem, we need to know that
arc length = r θ where θ is the central angle in radians.
We're given
r = 6 (units)
length of minor arc AB = 4pi
so we need to calculate the central angle, θ
Rearrange equation at the beginning,
θ = (arc length) / r = 4pi / 6 = 2pi /3
Answer: the central angle is 2pi/3 radians, or (2pi/3)*(180/pi) degrees = 120 degrees
17. RQ is the same as PS.
PS = -1 + 4x
RQ = 3x + 3
-1 + 4x = 3x + 3
4x = 3x + 4
x = 4
Now plug that into RQ.
3(4) + 3 = RQ
15 = RQ
18. Angles G and E are equal to each other.
G = 5x - 9
E = 3x + 11
5x - 9 = 3x + 11
5x = 3x + 20
2x = 20
x = 10
Plug that x into G.
5(10) - 9
41 = G
19. TE and EV are equal to each other.
TE = 4 + 2x
EV = 4x - 4
4 + 2x = 4x - 4
2x = 4x - 8
-2x = -8
x = 4
Plug that into TE.
4 + 2(4)
12 = TE
20. DB and BF are equal.
DB = 5x - 1
BF = 5 + 3x
5x - 1 = 5 + 3x
5x = 6 + 3x
2x = 6
x = 3
Plug that into DB.
5(3) - 1
14 = DB
Answer:
9 x (x +5) = 185
Step-by-step explanation:
I'm pretty sure this is how you write it
Yes, they're equivalent values.
-73 ≥ 15 + 11x
so the first thing you should do is to add -15 on both sides of the equation so you will have:
-73 -15 ≥ 11x
- 88 ≥ 11x
so the answer is:
-88/11 ≥ x or -8 ≥ x :)))
i hope this is helpful
have a nice day
