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Ugo [173]
3 years ago
8

A BMW I-8 has N advertised rate of acceleration of 6.39 m/s to the second power. Based in the advertised date of acceleration, w

hat would the velocity of a bmw I-8, starting from rest, in 4.20 seconds
Mathematics
1 answer:
igomit [66]3 years ago
5 0

Answer:

3.43

Step-by-step explanation:

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What if you divide it by 100?
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Jackson is buying a good chain that had an original price of $795 but is advertised as 65% off. Sales tax of 8.50% is applied to
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$560.673 is how much that nice chain would cost
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3 years ago
-7b&lt; -35<br> =less than or equal two
timama [110]

Answer:

b>5

=greater than or equal too

Step-by-step explanation:

divide -35 by -5, and since you are dividing by a negative, the sign flips

6 0
3 years ago
How can you write the expression with rationalized denominator? 2+sqrt3(3)/sqrt3(6)
joja [24]
So we have a 6 at the bottom, and the root is 3, so hmm how to take it out, simple enough, just let's get something to make the 6 a 6³, so it comes out of the root

so 

\bf \cfrac{2+\sqrt[3]{3}}{\sqrt[3]{6}}\cdot \cfrac{\sqrt[3]{6^2}}{\sqrt[3]{6^2}}\implies \cfrac{(2+\sqrt[3]{3})(\sqrt[3]{6^2})}{(\sqrt[3]{6})(\sqrt[3]{6^2})}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3}\cdot \sqrt[3]{36}}{\sqrt[3]{6^3}}&#10;\\\\\\&#10;\cfrac{2\sqrt[3]{36}+\sqrt[3]{3\cdot 36}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{108}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3^3\cdot 4}}{6}&#10;\\\\\\&#10;\cfrac{2\sqrt[3]{36}+3\sqrt[3]{ 4}}{6}
8 0
3 years ago
How do you do this???????????????????
Akimi4 [234]
The volume of water that goes into the hose is the same as the volume of water that comes out the nozzle. This means the velocity is inversely proportional to the area. The area is proportional to the square of the diameter.

Taken together, these facts mean that if the diameter is divided by a factor of 3, the velocity is multiplied by a factor of 3^2 = 9.

Nozzle velocity = 3^2 * entering velocity
.. = 9 * (4 m/s)
Nozzle velocity = 36 m/s . . . . . . . . . corresponding to selection A
7 0
3 years ago
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