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IgorC [24]
3 years ago
12

Classify each pair of numbered angles as corresponding, alternate interior, alternate exterior, or none of these.

Mathematics
1 answer:
ella [17]3 years ago
3 0

all are corespondent to each lateral line

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Morgan started the year with $615 in the bank and is saving $25 per week Kendall started with $975 and is spending $15 per week
gulaghasi [49]

Answer:

Step-by-step explanation:

You can represent Morgan's scenario with the expression, 25w + 615, and you can represent Kendall's scenario with the expression, 15w + 975.  To find out when they both have the same amount of money in their accounts, you set them equal to each other and solve for w:

25w + 615 = 15w + 975

25w = 15w + 360

10w = 360

w = 36

Morgan and Kendall will have the same amount of money after 36 weeks.

4 0
3 years ago
Help pls draw the answer
VLD [36.1K]

Answer:

t greater than or less than -10

Step-by-step explanation:

4 0
3 years ago
A teacher weighed 145 lbs in 1986 and weighs 190 lbs in 2007. What is the rate of change in weight? HELP
marishachu [46]

Answer:

c

Step-by-step explanation:

she gained 45 pounds which is 15/7 of 145

8 0
3 years ago
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C. Identify the following as a constant, linear, or absolute value
bija089 [108]

Answer:

here is the answer bae. Feel free to ask for more

6 0
3 years ago
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Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F.
Tems11 [23]

Answer:

The area of the triangle is  \sqrt{3}

Step-by-step explanation:

Given:

Coordinates D (0, 0), E (1, 1)

Angle  ∠DEF = 60°

△DEF is a Right triangle

To Find:

The area of the triangle

Solution:

The area of the triangle is  = \frac{1}{2}(base \times height)

Here the base is Distance between D and E

calculation the distance using the distance formula, we get

DE  = \sqrt{(0-1)^2 + (0-1)^2}

DE =\sqrt{(-1) ^2 + (-1)^2

DE = \sqrt{1+1}

DE = \sqrt{2}

Base = \sqrt{2}

Height is DF

DF =tan(60^{\circ}) \times DE

DF = \sqrt{3} \times DE

DF = \sqrt{3} \times\sqrt{2}

Now, the area of the triangle is

= \frac{1}{2}({\sqrt{2})(\sqrt{3} \times \sqrt{2})

=\frac{1}{2}({\sqrt{2})(\sqrt{3} \sqrt{2})

=\frac{1}{2}(2\sqrt{3} )

=\sqrt{3}

6 0
3 years ago
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